leetcode-problemset/leetcode-cn/originData/add-without-plus-lcci.json

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        "question": {
            "questionId": "1000025",
            "questionFrontendId": "面试题 17.01",
            "categoryTitle": "LCCI",
            "boundTopicId": 93177,
            "title": "Add Without Plus LCCI",
            "titleSlug": "add-without-plus-lcci",
            "content": "<p>Write a function that adds two numbers. You should not use + or any arithmetic operators.</p>\r\n\r\n<p><strong>Example:</strong></p>\r\n\r\n<pre>\r\n<strong>Input:</strong> a = 1, b = 1\r\n<strong>Output:</strong> 2</pre>\r\n\r\n<p>&nbsp;</p>\r\n\r\n<p><strong>Note: </strong></p>\r\n\r\n<ul>\r\n\t<li><code>a</code>&nbsp;and&nbsp;<code>b</code>&nbsp;may be 0 or negative.</li>\r\n\t<li>The result fits in 32-bit integer.</li>\r\n</ul>\r\n",
            "translatedTitle": "不用加号的加法",
            "translatedContent": "<p>设计一个函数把两个数字相加。不得使用 + 或者其他算术运算符。</p>\n\n<p><strong>示例:</strong></p>\n\n<pre><strong>输入:</strong> a = 1, b = 1\n<strong>输出:</strong> 2</pre>\n\n<p>&nbsp;</p>\n\n<p><strong>提示：</strong></p>\n\n<ul>\n\t<li><code>a</code>,&nbsp;<code>b</code>&nbsp;均可能是负数或 0</li>\n\t<li>结果不会溢出 32 位整数</li>\n</ul>\n",
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            "hints": [
                "手动（慢慢地）完成二进制加法，尝试真正理解发生了什么。",
                "你可以把二进制加法看成是对数字的每一位进行迭代、两位进行加和，并在必要时进位。你也可以对操作进行分组。如果首先对每位相加（不进位）会怎样？之后，你可以再处理进位。",
                "只关注上面的一个步骤。如果你“忘记”进位，那么加法操作会是什么样子?",
                "仅相加步骤就可以做如下转化：1 + 1 -> 0，1 + 0 -> 1，0 + 1 -> 1，0 + 0 -> 0。没有+号要怎么做?",
                "可以使用XOR执行加法步骤。",
                "现在关注进位。在什么情况下两个值会进位？如何使用进位？",
                "进位在1 + 1时发生。如何将进位应用到数值中？",
                "可以用AND运算来计算进位。如何使用它？",
                "你可能需要不止一次地执行加法/进位操作。将进位加到和中可能会产生新的进位值"
            ],
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