leetcode-problemset/leetcode-cn/originData/[no content]maximum-gcd-sum-of-a-subarray.json

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            "categoryTitle": "Algorithms",
            "boundTopicId": 2538161,
            "title": "Maximum GCD-Sum of a Subarray",
            "titleSlug": "maximum-gcd-sum-of-a-subarray",
            "content": null,
            "translatedTitle": "子数组的最大 GCD-Sum",
            "translatedContent": null,
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            "difficulty": "Hard",
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                {
                    "name": "Array",
                    "slug": "array",
                    "translatedName": "数组",
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                {
                    "name": "Math",
                    "slug": "math",
                    "translatedName": "数学",
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                {
                    "name": "Binary Search",
                    "slug": "binary-search",
                    "translatedName": "二分查找",
                    "__typename": "TopicTagNode"
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                {
                    "name": "Number Theory",
                    "slug": "number-theory",
                    "translatedName": "数论",
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            "hints": [
                "Try to answer the query of asking GCD of a subarray in <code>O(1)</code> using sparse tables and preprocessing.",
                "For every index <code>L</code>, let’s find the subarray starting at the index <code>L</code> and maximizing gcd-sum.",
                "Use the fact that if <code>L</code> is fixed, then by adding one more element to the end of a subarray, two things can happen: the gcd remains the same as the last gcd or becomes at least half of the last one.",
                "Now we can use binary search to find the last index <code>R</code> such that gcd of the elements of <code>nums[L..R]</code> would be equal to <code>nums[L]</code>.",
                "Now add <code>nums[R + 1]</code> to the current subarray and continue the process to find the last index that has the same gcd as the current gcd of elements."
            ],
            "solution": null,
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            "sampleTestCase": "[2,1,4,4,4,2]\n2",
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