mirror of
https://gitee.com/coder-xiaomo/leetcode-problemset
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191 lines
26 KiB
JSON
191 lines
26 KiB
JSON
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"title": "Eat Pizzas!",
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"content": "<p>You are given an integer array <code>pizzas</code> of size <code>n</code>, where <code>pizzas[i]</code> represents the weight of the <code>i<sup>th</sup></code> pizza. Every day, you eat <strong>exactly</strong> 4 pizzas. Due to your incredible metabolism, when you eat pizzas of weights <code>W</code>, <code>X</code>, <code>Y</code>, and <code>Z</code>, where <code>W <= X <= Y <= Z</code>, you gain the weight of only 1 pizza!</p>\n\n<ul>\n\t<li>On <strong><span style=\"box-sizing: border-box; margin: 0px; padding: 0px;\">odd-numbered</span></strong> days <strong>(1-indexed)</strong>, you gain a weight of <code>Z</code>.</li>\n\t<li>On <strong>even-numbered</strong> days, you gain a weight of <code>Y</code>.</li>\n</ul>\n\n<p>Find the <strong>maximum</strong> total weight you can gain by eating <strong>all</strong> pizzas optimally.</p>\n\n<p><strong>Note</strong>: It is guaranteed that <code>n</code> is a multiple of 4, and each pizza can be eaten only once.</p>\n\n<p> </p>\n<p><strong class=\"example\">Example 1:</strong></p>\n\n<div class=\"example-block\">\n<p><strong>Input:</strong> <span class=\"example-io\">pizzas = [1,2,3,4,5,6,7,8]</span></p>\n\n<p><strong>Output:</strong> <span class=\"example-io\">14</span></p>\n\n<p><strong>Explanation:</strong></p>\n\n<ul>\n\t<li>On day 1, you eat pizzas at indices <code>[1, 2, 4, 7] = [2, 3, 5, 8]</code>. You gain a weight of 8.</li>\n\t<li>On day 2, you eat pizzas at indices <code>[0, 3, 5, 6] = [1, 4, 6, 7]</code>. You gain a weight of 6.</li>\n</ul>\n\n<p>The total weight gained after eating all the pizzas is <code>8 + 6 = 14</code>.</p>\n</div>\n\n<p><strong class=\"example\">Example 2:</strong></p>\n\n<div class=\"example-block\">\n<p><strong>Input:</strong> <span class=\"example-io\">pizzas = [2,1,1,1,1,1,1,1]</span></p>\n\n<p><strong>Output:</strong> <span class=\"example-io\">3</span></p>\n\n<p><strong>Explanation:</strong></p>\n\n<ul>\n\t<li>On day 1, you eat pizzas at indices <code>[4, 5, 6, 0] = [1, 1, 1, 2]</code>. You gain a weight of 2.</li>\n\t<li>On day 2, you eat pizzas at indices <code>[1, 2, 3, 7] = [1, 1, 1, 1]</code>. You gain a weight of 1.</li>\n</ul>\n\n<p>The total weight gained after eating all the pizzas is <code>2 + 1 = 3.</code></p>\n</div>\n\n<p> </p>\n<p><strong>Constraints:</strong></p>\n\n<ul>\n\t<li><code>4 <= n == pizzas.length <= 2 * 10<sup><span style=\"font-size: 10.8333px;\">5</span></sup></code></li>\n\t<li><code>1 <= pizzas[i] <= 10<sup>5</sup></code></li>\n\t<li><code>n</code> is a multiple of 4.</li>\n</ul>\n",
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"translatedTitle": "吃披萨",
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"translatedContent": "<p>给你一个长度为 <code>n</code> 的整数数组 <code>pizzas</code>,其中 <code>pizzas[i]</code> 表示第 <code>i</code> 个披萨的重量。每天你会吃 <strong>恰好</strong> 4 个披萨。由于你的新陈代谢能力惊人,当你吃重量为 <code>W</code>、<code>X</code>、<code>Y</code> 和 <code>Z</code> 的披萨(其中 <code>W <= X <= Y <= Z</code>)时,你只会增加 1 个披萨的重量!体重增加规则如下:</p>\n\n<ul>\n\t<li>在 <strong><span style=\"box-sizing: border-box; margin: 0px; padding: 0px;\">奇数天</span></strong>(按 <strong>1 开始计数</strong>)你会增加 <code>Z</code> 的重量。</li>\n\t<li>在 <strong>偶数天</strong>,你会增加 <code>Y</code> 的重量。</li>\n</ul>\n\n<p>请你设计吃掉 <strong>所有 </strong>披萨的最优方案,并计算你可以增加的 <strong>最大 </strong>总重量。</p>\n\n<p><strong>注意:</strong>保证 <code>n</code> 是 4 的倍数,并且每个披萨只吃一次。</p>\n\n<p> </p>\n\n<p><strong class=\"example\">示例 1:</strong></p>\n\n<div class=\"example-block\">\n<p><strong>输入:</strong> <span class=\"example-io\">pizzas = [1,2,3,4,5,6,7,8]</span></p>\n\n<p><strong>输出:</strong> <span class=\"example-io\">14</span></p>\n\n<p><strong>解释:</strong></p>\n\n<ul>\n\t<li>第 1 天,你吃掉下标为 <code>[1, 2, 4, 7] = [2, 3, 5, 8]</code> 的披萨。你增加的重量为 8。</li>\n\t<li>第 2 天,你吃掉下标为 <code>[0, 3, 5, 6] = [1, 4, 6, 7]</code> 的披萨。你增加的重量为 6。</li>\n</ul>\n\n<p>吃掉所有披萨后,你增加的总重量为 <code>8 + 6 = 14</code>。</p>\n</div>\n\n<p><strong class=\"example\">示例 2:</strong></p>\n\n<div class=\"example-block\">\n<p><strong>输入:</strong> <span class=\"example-io\">pizzas = [2,1,1,1,1,1,1,1]</span></p>\n\n<p><strong>输出:</strong> <span class=\"example-io\">3</span></p>\n\n<p><strong>解释:</strong></p>\n\n<ul>\n\t<li>第 1 天,你吃掉下标为 <code>[4, 5, 6, 0] = [1, 1, 1, 2]</code> 的披萨。你增加的重量为 2。</li>\n\t<li>第 2 天,你吃掉下标为 <code>[1, 2, 3, 7] = [1, 1, 1, 1]</code> 的披萨。你增加的重量为 1。</li>\n</ul>\n\n<p>吃掉所有披萨后,你增加的总重量为 <code>2 + 1 = 3</code>。</p>\n</div>\n\n<p> </p>\n\n<p><strong>提示:</strong></p>\n\n<ul>\n\t<li><code>4 <= n == pizzas.length <= 2 * 10<sup><span style=\"font-size: 10.8333px;\">5</span></sup></code></li>\n\t<li><code>1 <= pizzas[i] <= 10<sup>5</sup></code></li>\n\t<li><code>n</code> 是 4 的倍数。</li>\n</ul>\n",
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"On odd-numbered days, it is optimal to pair the smallest three and the largest one.",
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"There will be ceil((n / 4) / 2) odd-numbered days. Select pizzas for all odd-numbered days first.",
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