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leetcode-problemset/leetcode-cn/problem (Chinese)/求关注者的数量 [find-followers-count].html
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<p>表:&nbsp;<code>Followers</code></p>
<pre>
+-------------+------+
| Column Name | Type |
+-------------+------+
| user_id | int |
| follower_id | int |
+-------------+------+
(user_id, follower_id) 是这个表的主键。
该表包含一个关注关系中关注者和用户的编号,其中关注者关注用户。</pre>
<p>&nbsp;</p>
<p>写出 SQL 语句,对于每一个用户,返回该用户的关注者数量。</p>
<p>&nbsp;<code>user_id</code>&nbsp;的顺序返回结果表。</p>
<p>查询结果的格式如下示例所示。</p>
<p>&nbsp;</p>
<p><strong>示例 1</strong></p>
<pre>
<strong>输入:</strong>
Followers 表:
+---------+-------------+
| user_id | follower_id |
+---------+-------------+
| 0 | 1 |
| 1 | 0 |
| 2 | 0 |
| 2 | 1 |
+---------+-------------+
<strong>输出:</strong>
+---------+----------------+
| user_id | followers_count|
+---------+----------------+
| 0 | 1 |
| 1 | 1 |
| 2 | 2 |
+---------+----------------+
<strong>解释:</strong>
0 的关注者有 {1}
1 的关注者有 {0}
2 的关注者有 {0,1}</pre>