mirror of
https://gitee.com/coder-xiaomo/leetcode-problemset
synced 2025-01-11 02:58:13 +08:00
46 lines
1.2 KiB
HTML
46 lines
1.2 KiB
HTML
<p>表: <code>Person</code></p>
|
||
|
||
<pre>
|
||
+-------------+---------+
|
||
| Column Name | Type |
|
||
+-------------+---------+
|
||
| id | int |
|
||
| email | varchar |
|
||
+-------------+---------+
|
||
id是该表的主键列。
|
||
该表的每一行包含一封电子邮件。电子邮件将不包含大写字母。
|
||
</pre>
|
||
|
||
<p> </p>
|
||
|
||
<p>编写一个 SQL <strong>删除语句</strong>来 <strong>删除</strong> 所有重复的电子邮件,只保留一个id最小的唯一电子邮件。</p>
|
||
|
||
<p>以 <strong>任意顺序</strong> 返回结果表。 (<strong>注意</strong>: 仅需要写删除语句,将自动对剩余结果进行查询)</p>
|
||
|
||
<p>查询结果格式如下所示。</p>
|
||
|
||
<p> </p>
|
||
|
||
<p> </p>
|
||
|
||
<p><strong>示例 1:</strong></p>
|
||
|
||
<pre>
|
||
<strong>输入:</strong>
|
||
Person 表:
|
||
+----+------------------+
|
||
| id | email |
|
||
+----+------------------+
|
||
| 1 | john@example.com |
|
||
| 2 | bob@example.com |
|
||
| 3 | john@example.com |
|
||
+----+------------------+
|
||
<strong>输出:</strong>
|
||
+----+------------------+
|
||
| id | email |
|
||
+----+------------------+
|
||
| 1 | john@example.com |
|
||
| 2 | bob@example.com |
|
||
+----+------------------+
|
||
<strong>解释:</strong> john@example.com重复两次。我们保留最小的Id = 1。</pre>
|