mirror of
https://gitee.com/coder-xiaomo/leetcode-problemset
synced 2025-01-11 02:58:13 +08:00
198 lines
16 KiB
JSON
198 lines
16 KiB
JSON
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"questionId": "567",
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"title": "Permutation in String",
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"titleSlug": "permutation-in-string",
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"content": "<p>Given two strings <code>s1</code> and <code>s2</code>, return <code>true</code><em> if </em><code>s2</code><em> contains a permutation of </em><code>s1</code><em>, or </em><code>false</code><em> otherwise</em>.</p>\n\n<p>In other words, return <code>true</code> if one of <code>s1</code>'s permutations is the substring of <code>s2</code>.</p>\n\n<p> </p>\n<p><strong>Example 1:</strong></p>\n\n<pre>\n<strong>Input:</strong> s1 = "ab", s2 = "eidbaooo"\n<strong>Output:</strong> true\n<strong>Explanation:</strong> s2 contains one permutation of s1 ("ba").\n</pre>\n\n<p><strong>Example 2:</strong></p>\n\n<pre>\n<strong>Input:</strong> s1 = "ab", s2 = "eidboaoo"\n<strong>Output:</strong> false\n</pre>\n\n<p> </p>\n<p><strong>Constraints:</strong></p>\n\n<ul>\n\t<li><code>1 <= s1.length, s2.length <= 10<sup>4</sup></code></li>\n\t<li><code>s1</code> and <code>s2</code> consist of lowercase English letters.</li>\n</ul>\n",
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"difficulty": "Medium",
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"exampleTestcases": "\"ab\"\n\"eidbaooo\"\n\"ab\"\n\"eidboaoo\"",
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"categoryTitle": "Algorithms",
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"code": "class Solution {\n\n /**\n * @param String $s1\n * @param String $s2\n * @return Boolean\n */\n function checkInclusion($s1, $s2) {\n \n }\n}",
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"langSlug": "racket",
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"code": "(define/contract (check-inclusion s1 s2)\n (-> string? string? boolean?)\n\n )",
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"lang": "Erlang",
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"langSlug": "erlang",
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"code": "-spec check_inclusion(S1 :: unicode:unicode_binary(), S2 :: unicode:unicode_binary()) -> boolean().\ncheck_inclusion(S1, S2) ->\n .",
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"lang": "Elixir",
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"langSlug": "elixir",
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"code": "defmodule Solution do\n @spec check_inclusion(s1 :: String.t, s2 :: String.t) :: boolean\n def check_inclusion(s1, s2) do\n\n end\nend",
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"stats": "{\"totalAccepted\": \"374.1K\", \"totalSubmission\": \"835K\", \"totalAcceptedRaw\": 374087, \"totalSubmissionRaw\": 834976, \"acRate\": \"44.8%\"}",
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"hints": [
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"Obviously, brute force will result in TLE. Think of something else.",
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"How will you check whether one string is a permutation of another string?",
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"One way is to sort the string and then compare. But, Is there a better way?",
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"If one string is a permutation of another string then they must one common metric. What is that?",
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"Both strings must have same character frequencies, if one is permutation of another. Which data structure should be used to store frequencies?",
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"What about hash table? An array of size 26?"
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],
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"solution": {
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"id": "121",
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"sampleTestCase": "\"ab\"\n\"eidbaooo\"",
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Java 8 features such as lambda expressions and stream API can be used. </p>\\r\\n\\r\\n<p>Most standard library headers are already included automatically for your convenience.</p>\\r\\n<p>Includes <code>Pair</code> class from https://docs.oracle.com/javase/8/javafx/api/javafx/util/Pair.html.</p>\"], \"python\": [\"Python\", \"<p><code>Python 2.7.12</code>.</p>\\r\\n\\r\\n<p>Most libraries are already imported automatically for your convenience, such as <a href=\\\"https://docs.python.org/2/library/array.html\\\" target=\\\"_blank\\\">array</a>, <a href=\\\"https://docs.python.org/2/library/bisect.html\\\" target=\\\"_blank\\\">bisect</a>, <a href=\\\"https://docs.python.org/2/library/collections.html\\\" target=\\\"_blank\\\">collections</a>. 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