mirror of
https://gitee.com/coder-xiaomo/leetcode-problemset
synced 2025-01-11 02:58:13 +08:00
38 lines
1.6 KiB
HTML
38 lines
1.6 KiB
HTML
<p>输入一个英文句子,翻转句子中单词的顺序,但单词内字符的顺序不变。为简单起见,标点符号和普通字母一样处理。例如输入字符串"I am a student. ",则输出"student. a am I"。</p>
|
||
|
||
<p> </p>
|
||
|
||
<p><strong>示例 1:</strong></p>
|
||
|
||
<pre><strong>输入:</strong> "<code>the sky is blue</code>"
|
||
<strong>输出: </strong>"<code>blue is sky the</code>"
|
||
</pre>
|
||
|
||
<p><strong>示例 2:</strong></p>
|
||
|
||
<pre><strong>输入:</strong> " hello world! "
|
||
<strong>输出: </strong>"world! hello"
|
||
<strong>解释: </strong>输入字符串可以在前面或者后面包含多余的空格,但是反转后的字符不能包括。
|
||
</pre>
|
||
|
||
<p><strong>示例 3:</strong></p>
|
||
|
||
<pre><strong>输入:</strong> "a good example"
|
||
<strong>输出: </strong>"example good a"
|
||
<strong>解释: </strong>如果两个单词间有多余的空格,将反转后单词间的空格减少到只含一个。
|
||
</pre>
|
||
|
||
<p> </p>
|
||
|
||
<p><strong>说明:</strong></p>
|
||
|
||
<ul>
|
||
<li>无空格字符构成一个单词。</li>
|
||
<li>输入字符串可以在前面或者后面包含多余的空格,但是反转后的字符不能包括。</li>
|
||
<li>如果两个单词间有多余的空格,将反转后单词间的空格减少到只含一个。</li>
|
||
</ul>
|
||
|
||
<p><strong>注意:</strong>本题与主站 151 题相同:<a href="https://leetcode-cn.com/problems/reverse-words-in-a-string/">https://leetcode-cn.com/problems/reverse-words-in-a-string/</a></p>
|
||
|
||
<p><strong>注意:</strong>此题对比原题有改动</p>
|