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leetcode-problemset/leetcode-cn/problem (Chinese)/猜数字大小 [guess-number-higher-or-lower].html
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<p>猜数字游戏的规则如下:</p>
<ul>
<li>每轮游戏,我都会从 <strong>1</strong> 到 <em><strong>n</strong></em> 随机选择一个数字。 请你猜选出的是哪个数字。</li>
<li>如果你猜错了,我会告诉你,你猜测的数字比我选出的数字是大了还是小了。</li>
</ul>
<p>你可以通过调用一个预先定义好的接口 <code>int guess(int num)</code> 来获取猜测结果,返回值一共有 3 种可能的情况(<code>-1</code><code>1</code> 或 <code>0</code></p>
<ul>
<li>-1我选出的数字比你猜的数字小 <code>pick < num</code></li>
<li>1我选出的数字比你猜的数字大 <code>pick > num</code></li>
<li>0我选出的数字和你猜的数字一样。恭喜你猜对了<code>pick == num</code></li>
</ul>
<p>返回我选出的数字。</p>
<p> </p>
<p><strong>示例 1</strong></p>
<pre>
<strong>输入:</strong>n = 10, pick = 6
<strong>输出:</strong>6
</pre>
<p><strong>示例 2</strong></p>
<pre>
<strong>输入:</strong>n = 1, pick = 1
<strong>输出:</strong>1
</pre>
<p><strong>示例 3</strong></p>
<pre>
<strong>输入:</strong>n = 2, pick = 1
<strong>输出:</strong>1
</pre>
<p><strong>示例 4</strong></p>
<pre>
<strong>输入:</strong>n = 2, pick = 2
<strong>输出:</strong>2
</pre>
<p> </p>
<p><strong>提示:</strong></p>
<ul>
<li><code>1 <= n <= 2<sup>31</sup> - 1</code></li>
<li><code>1 <= pick <= n</code></li>
</ul>