mirror of
				https://gitee.com/coder-xiaomo/leetcode-problemset
				synced 2025-11-04 19:53:12 +08:00 
			
		
		
		
	
		
			
				
	
	
		
			41 lines
		
	
	
		
			1.7 KiB
		
	
	
	
		
			HTML
		
	
	
	
	
	
			
		
		
	
	
			41 lines
		
	
	
		
			1.7 KiB
		
	
	
	
		
			HTML
		
	
	
	
	
	
<p>给你一个由若干 0 和 1 组成的字符串 <code>s</code> ,请你计算并返回将该字符串分割成两个 <strong>非空</strong> 子字符串(即 <strong>左</strong> 子字符串和 <strong>右</strong> 子字符串)所能获得的最大得分。</p>
 | 
						||
 | 
						||
<p>「分割字符串的得分」为 <strong>左</strong> 子字符串中 <strong>0</strong> 的数量加上 <strong>右</strong> 子字符串中 <strong>1</strong> 的数量。</p>
 | 
						||
 | 
						||
<p> </p>
 | 
						||
 | 
						||
<p><strong>示例 1:</strong></p>
 | 
						||
 | 
						||
<pre><strong>输入:</strong>s = "011101"
 | 
						||
<strong>输出:</strong>5 
 | 
						||
<strong>解释:</strong>
 | 
						||
将字符串 s 划分为两个非空子字符串的可行方案有:
 | 
						||
左子字符串 = "0" 且 右子字符串 = "11101",得分 = 1 + 4 = 5 
 | 
						||
左子字符串 = "01" 且 右子字符串 = "1101",得分 = 1 + 3 = 4 
 | 
						||
左子字符串 = "011" 且 右子字符串 = "101",得分 = 1 + 2 = 3 
 | 
						||
左子字符串 = "0111" 且 右子字符串 = "01",得分 = 1 + 1 = 2 
 | 
						||
左子字符串 = "01110" 且 右子字符串 = "1",得分 = 2 + 1 = 3
 | 
						||
</pre>
 | 
						||
 | 
						||
<p><strong>示例 2:</strong></p>
 | 
						||
 | 
						||
<pre><strong>输入:</strong>s = "00111"
 | 
						||
<strong>输出:</strong>5
 | 
						||
<strong>解释:</strong>当 左子字符串 = "00" 且 右子字符串 = "111" 时,我们得到最大得分 = 2 + 3 = 5
 | 
						||
</pre>
 | 
						||
 | 
						||
<p><strong>示例 3:</strong></p>
 | 
						||
 | 
						||
<pre><strong>输入:</strong>s = "1111"
 | 
						||
<strong>输出:</strong>3
 | 
						||
</pre>
 | 
						||
 | 
						||
<p> </p>
 | 
						||
 | 
						||
<p><strong>提示:</strong></p>
 | 
						||
 | 
						||
<ul>
 | 
						||
	<li><code>2 <= s.length <= 500</code></li>
 | 
						||
	<li>字符串 <code>s</code> 仅由字符 <code>'0'</code> 和 <code>'1'</code> 组成。</li>
 | 
						||
</ul>
 |