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leetcode-problemset/leetcode-cn/problem (Chinese)/两数相除 [divide-two-integers].html
2022-03-29 12:43:11 +08:00

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<p>给定两个整数,被除数&nbsp;<code>dividend</code>&nbsp;和除数&nbsp;<code>divisor</code>。将两数相除,要求不使用乘法、除法和 mod 运算符。</p>
<p>返回被除数&nbsp;<code>dividend</code>&nbsp;除以除数&nbsp;<code>divisor</code>&nbsp;得到的商。</p>
<p>整数除法的结果应当截去(<code>truncate</code>)其小数部分,例如:<code>truncate(8.345) = 8</code> 以及 <code>truncate(-2.7335) = -2</code></p>
<p>&nbsp;</p>
<p><strong>示例&nbsp;1:</strong></p>
<pre><strong>输入:</strong> dividend = 10, divisor = 3
<strong>输出:</strong> 3
<strong>解释: </strong>10/3 = truncate(3.33333..) = truncate(3) = 3</pre>
<p><strong>示例&nbsp;2:</strong></p>
<pre><strong>输入:</strong> dividend = 7, divisor = -3
<strong>输出:</strong> -2
<strong>解释:</strong> 7/-3 = truncate(-2.33333..) = -2</pre>
<p>&nbsp;</p>
<p><strong>提示:</strong></p>
<ul>
<li>被除数和除数均为 32 位有符号整数。</li>
<li>除数不为&nbsp;0。</li>
<li>假设我们的环境只能存储 32 位有符号整数,其数值范围是 [&minus;2<sup>31</sup>,&nbsp; 2<sup>31&nbsp;</sup>&minus; 1]。本题中,如果除法结果溢出,则返回 2<sup>31&nbsp;</sup>&minus; 1。</li>
</ul>