mirror of
				https://gitee.com/coder-xiaomo/leetcode-problemset
				synced 2025-11-04 11:43:12 +08:00 
			
		
		
		
	
		
			
				
	
	
		
			33 lines
		
	
	
		
			983 B
		
	
	
	
		
			HTML
		
	
	
	
	
	
			
		
		
	
	
			33 lines
		
	
	
		
			983 B
		
	
	
	
		
			HTML
		
	
	
	
	
	
<p>给定一个字符串 <code>s</code> 和一个整数 <code>k</code>,从字符串开头算起,每计数至 <code>2k</code> 个字符,就反转这 <code>2k</code> 字符中的前 <code>k</code> 个字符。</p>
 | 
						||
 | 
						||
<ul>
 | 
						||
	<li>如果剩余字符少于 <code>k</code> 个,则将剩余字符全部反转。</li>
 | 
						||
	<li>如果剩余字符小于 <code>2k</code> 但大于或等于 <code>k</code> 个,则反转前 <code>k</code> 个字符,其余字符保持原样。</li>
 | 
						||
</ul>
 | 
						||
 | 
						||
<p> </p>
 | 
						||
 | 
						||
<p><strong>示例 1:</strong></p>
 | 
						||
 | 
						||
<pre>
 | 
						||
<strong>输入:</strong>s = "abcdefg", k = 2
 | 
						||
<strong>输出:</strong>"bacdfeg"
 | 
						||
</pre>
 | 
						||
 | 
						||
<p><strong>示例 2:</strong></p>
 | 
						||
 | 
						||
<pre>
 | 
						||
<strong>输入:</strong>s = "abcd", k = 2
 | 
						||
<strong>输出:</strong>"bacd"
 | 
						||
</pre>
 | 
						||
 | 
						||
<p> </p>
 | 
						||
 | 
						||
<p><strong>提示:</strong></p>
 | 
						||
 | 
						||
<ul>
 | 
						||
	<li><code>1 <= s.length <= 10<sup>4</sup></code></li>
 | 
						||
	<li><code>s</code> 仅由小写英文组成</li>
 | 
						||
	<li><code>1 <= k <= 10<sup>4</sup></code></li>
 | 
						||
</ul>
 |