leetcode-problemset/leetcode/originData/time-taken-to-mark-all-nodes.json

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        "question": {
            "questionId": "3532",
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            "title": "Time Taken to Mark All Nodes",
            "titleSlug": "time-taken-to-mark-all-nodes",
            "content": "<p>There exists an <strong>undirected</strong> tree with <code>n</code> nodes numbered <code>0</code> to <code>n - 1</code>. You are given a 2D integer array <code>edges</code> of length <code>n - 1</code>, where <code>edges[i] = [u<sub>i</sub>, v<sub>i</sub>]</code> indicates that there is an edge between nodes <code>u<sub>i</sub></code> and <code>v<sub>i</sub></code> in the tree.</p>\n\n<p>Initially, <strong>all</strong> nodes are <strong>unmarked</strong>. For each node <code>i</code>:</p>\n\n<ul>\n\t<li>If <code>i</code> is odd, the node will get marked at time <code>x</code> if there is <strong>at least</strong> one node <em>adjacent</em> to it which was marked at time <code>x - 1</code>.</li>\n\t<li>If <code>i</code> is even, the node will get marked at time <code>x</code> if there is <strong>at least</strong> one node <em>adjacent</em> to it which was marked at time <code>x - 2</code>.</li>\n</ul>\n\n<p>Return an array <code>times</code> where <code>times[i]</code> is the time when all nodes get marked in the tree, if you mark node <code>i</code> at time <code>t = 0</code>.</p>\n\n<p><strong>Note</strong> that the answer for each <code>times[i]</code> is <strong>independent</strong>, i.e. when you mark node <code>i</code> all other nodes are <em>unmarked</em>.</p>\n\n<p>&nbsp;</p>\n<p><strong class=\"example\">Example 1:</strong></p>\n\n<div class=\"example-block\">\n<p><strong>Input:</strong> <span class=\"example-io\">edges = [[0,1],[0,2]]</span></p>\n\n<p><strong>Output:</strong> [2,4,3]</p>\n\n<p><strong>Explanation:</strong></p>\n\n<p><img alt=\"\" src=\"https://assets.leetcode.com/uploads/2024/06/01/screenshot-2024-06-02-122236.png\" style=\"width: 500px; height: 241px;\" /></p>\n\n<ul>\n\t<li>For <code>i = 0</code>:\n\n\t<ul>\n\t\t<li>Node 1 is marked at <code>t = 1</code>, and Node 2 at <code>t = 2</code>.</li>\n\t</ul>\n\t</li>\n\t<li>For <code>i = 1</code>:\n\t<ul>\n\t\t<li>Node 0 is marked at <code>t = 2</code>, and Node 2 at <code>t = 4</code>.</li>\n\t</ul>\n\t</li>\n\t<li>For <code>i = 2</code>:\n\t<ul>\n\t\t<li>Node 0 is marked at <code>t = 2</code>, and Node 1 at <code>t = 3</code>.</li>\n\t</ul>\n\t</li>\n</ul>\n</div>\n\n<p><strong class=\"example\">Example 2:</strong></p>\n\n<div class=\"example-block\">\n<p><strong>Input:</strong> <span class=\"example-io\">edges = [[0,1]]</span></p>\n\n<p><strong>Output:</strong> [1,2]</p>\n\n<p><strong>Explanation:</strong></p>\n\n<p><img alt=\"\" src=\"https://assets.leetcode.com/uploads/2024/06/01/screenshot-2024-06-02-122249.png\" style=\"width: 500px; height: 257px;\" /></p>\n\n<ul>\n\t<li>For <code>i = 0</code>:\n\n\t<ul>\n\t\t<li>Node 1 is marked at <code>t = 1</code>.</li>\n\t</ul>\n\t</li>\n\t<li>For <code>i = 1</code>:\n\t<ul>\n\t\t<li>Node 0 is marked at <code>t = 2</code>.</li>\n\t</ul>\n\t</li>\n</ul>\n</div>\n\n<p><strong class=\"example\">Example 3:</strong></p>\n\n<div class=\"example-block\">\n<p><strong>Input:</strong> <span class=\"example-io\">edges = </span>[[2,4],[0,1],[2,3],[0,2]]</p>\n\n<p><strong>Output:</strong> [4,6,3,5,5]</p>\n\n<p><strong>Explanation:</strong></p>\n\n<p><img alt=\"\" src=\"https://assets.leetcode.com/uploads/2024/06/03/screenshot-2024-06-03-210550.png\" style=\"height: 266px; width: 500px;\" /></p>\n</div>\n\n<p>&nbsp;</p>\n<p><strong>Constraints:</strong></p>\n\n<ul>\n\t<li><code>2 &lt;= n &lt;= 10<sup>5</sup></code></li>\n\t<li><code>edges.length == n - 1</code></li>\n\t<li><code>edges[i].length == 2</code></li>\n\t<li><code>0 &lt;= edges[i][0], edges[i][1] &lt;= n - 1</code></li>\n\t<li>The input is generated such that <code>edges</code> represents a valid tree.</li>\n</ul>\n",
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                    "lang": "C++",
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                    "code": "class Solution {\npublic:\n    vector<int> timeTaken(vector<vector<int>>& edges) {\n        \n    }\n};",
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                    "code": "class Solution(object):\n    def timeTaken(self, edges):\n        \"\"\"\n        :type edges: List[List[int]]\n        :rtype: List[int]\n        \"\"\"\n        ",
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                    "code": "/**\n * Note: The returned array must be malloced, assume caller calls free().\n */\nint* timeTaken(int** edges, int edgesSize, int* edgesColSize, int* returnSize) {\n    \n}",
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                    "code": "public class Solution {\n    public int[] TimeTaken(int[][] edges) {\n        \n    }\n}",
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                    "code": "/**\n * @param {number[][]} edges\n * @return {number[]}\n */\nvar timeTaken = function(edges) {\n    \n};",
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                    "code": "function timeTaken(edges: number[][]): number[] {\n    \n};",
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                    "code": "class Solution {\n\n    /**\n     * @param Integer[][] $edges\n     * @return Integer[]\n     */\n    function timeTaken($edges) {\n        \n    }\n}",
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                    "code": "class Solution {\n    func timeTaken(_ edges: [[Int]]) -> [Int] {\n        \n    }\n}",
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                    "code": "class Solution {\n    fun timeTaken(edges: Array<IntArray>): IntArray {\n        \n    }\n}",
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                    "lang": "Dart",
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                    "code": "class Solution {\n  List<int> timeTaken(List<List<int>> edges) {\n    \n  }\n}",
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                    "lang": "Go",
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                    "code": "func timeTaken(edges [][]int) []int {\n    \n}",
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                    "code": "# @param {Integer[][]} edges\n# @return {Integer[]}\ndef time_taken(edges)\n    \nend",
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                    "code": "object Solution {\n    def timeTaken(edges: Array[Array[Int]]): Array[Int] = {\n        \n    }\n}",
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                    "code": "impl Solution {\n    pub fn time_taken(edges: Vec<Vec<i32>>) -> Vec<i32> {\n        \n    }\n}",
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                    "lang": "Racket",
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                    "lang": "Erlang",
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                    "code": "-spec time_taken(Edges :: [[integer()]]) -> [integer()].\ntime_taken(Edges) ->\n  .",
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                    "code": "defmodule Solution do\n  @spec time_taken(edges :: [[integer]]) :: [integer]\n  def time_taken(edges) do\n    \n  end\nend",
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            "hints": [
                "Can we use dp on trees?",
                "Store the two most distant children for each node.",
                "When re-rooting the tree, keep a variable for distance to the root node."
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