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{
"data": {
"question": {
"questionId": "3232",
"questionFrontendId": "2941",
"categoryTitle": "Algorithms",
"boundTopicId": 2538161,
"title": "Maximum GCD-Sum of a Subarray",
"titleSlug": "maximum-gcd-sum-of-a-subarray",
"content": null,
"translatedTitle": "子数组的最大 GCD-Sum",
"translatedContent": null,
"isPaidOnly": true,
"difficulty": "Hard",
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"topicTags": [
{
"name": "Array",
"slug": "array",
"translatedName": "数组",
"__typename": "TopicTagNode"
},
{
"name": "Math",
"slug": "math",
"translatedName": "数学",
"__typename": "TopicTagNode"
},
{
"name": "Binary Search",
"slug": "binary-search",
"translatedName": "二分查找",
"__typename": "TopicTagNode"
},
{
"name": "Number Theory",
"slug": "number-theory",
"translatedName": "数论",
"__typename": "TopicTagNode"
}
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"stats": "{\"totalAccepted\": \"366\", \"totalSubmission\": \"672\", \"totalAcceptedRaw\": 366, \"totalSubmissionRaw\": 672, \"acRate\": \"54.5%\"}",
"hints": [
"Try to answer the query of asking GCD of a subarray in <code>O(1)</code> using sparse tables and preprocessing.",
"For every index <code>L</code>, lets find the subarray starting at the index <code>L</code> and maximizing gcd-sum.",
"Use the fact that if <code>L</code> is fixed, then by adding one more element to the end of a subarray, two things can happen: the gcd remains the same as the last gcd or becomes at least half of the last one.",
"Now we can use binary search to find the last index <code>R</code> such that gcd of the elements of <code>nums[L..R]</code> would be equal to <code>nums[L]</code>.",
"Now add <code>nums[R + 1]</code> to the current subarray and continue the process to find the last index that has the same gcd as the current gcd of elements."
],
"solution": null,
"status": null,
"sampleTestCase": "[2,1,4,4,4,2]\n2",
"metaData": "{\n \"name\": \"maxGcdSum\",\n \"params\": [\n {\n \"name\": \"nums\",\n \"type\": \"integer[]\"\n },\n {\n \"type\": \"integer\",\n \"name\": \"k\"\n }\n ],\n \"return\": {\n \"type\": \"long\"\n }\n}",
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