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leetcode-problemset/leetcode/originData/minimum-array-sum.json
2024-11-29 17:49:27 +08:00

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{
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"title": "Minimum Array Sum",
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"content": "<p>You are given an integer array <code>nums</code> and three integers <code>k</code>, <code>op1</code>, and <code>op2</code>.</p>\n\n<p>You can perform the following operations on <code>nums</code>:</p>\n\n<ul>\n\t<li><strong>Operation 1</strong>: Choose an index <code>i</code> and divide <code>nums[i]</code> by 2, <strong>rounding up</strong> to the nearest whole number. You can perform this operation at most <code>op1</code> times, and not more than <strong>once</strong> per index.</li>\n\t<li><strong>Operation 2</strong>: Choose an index <code>i</code> and subtract <code>k</code> from <code>nums[i]</code>, but only if <code>nums[i]</code> is greater than or equal to <code>k</code>. You can perform this operation at most <code>op2</code> times, and not more than <strong>once</strong> per index.</li>\n</ul>\n\n<p><strong>Note:</strong> Both operations can be applied to the same index, but at most once each.</p>\n\n<p>Return the <strong>minimum</strong> possible <strong>sum</strong> of all elements in <code>nums</code> after performing any number of operations.</p>\n\n<p>&nbsp;</p>\n<p><strong class=\"example\">Example 1:</strong></p>\n\n<div class=\"example-block\">\n<p><strong>Input:</strong> <span class=\"example-io\">nums = [2,8,3,19,3], k = 3, op1 = 1, op2 = 1</span></p>\n\n<p><strong>Output:</strong> <span class=\"example-io\">23</span></p>\n\n<p><strong>Explanation:</strong></p>\n\n<ul>\n\t<li>Apply Operation 2 to <code>nums[1] = 8</code>, making <code>nums[1] = 5</code>.</li>\n\t<li>Apply Operation 1 to <code>nums[3] = 19</code>, making <code>nums[3] = 10</code>.</li>\n\t<li>The resulting array becomes <code>[2, 5, 3, 10, 3]</code>, which has the minimum possible sum of 23 after applying the operations.</li>\n</ul>\n</div>\n\n<p><strong class=\"example\">Example 2:</strong></p>\n\n<div class=\"example-block\">\n<p><strong>Input:</strong> <span class=\"example-io\">nums = [2,4,3], k = 3, op1 = 2, op2 = 1</span></p>\n\n<p><strong>Output:</strong> <span class=\"example-io\">3</span></p>\n\n<p><strong>Explanation:</strong></p>\n\n<ul>\n\t<li>Apply Operation 1 to <code>nums[0] = 2</code>, making <code>nums[0] = 1</code>.</li>\n\t<li>Apply Operation 1 to <code>nums[1] = 4</code>, making <code>nums[1] = 2</code>.</li>\n\t<li>Apply Operation 2 to <code>nums[2] = 3</code>, making <code>nums[2] = 0</code>.</li>\n\t<li>The resulting array becomes <code>[1, 2, 0]</code>, which has the minimum possible sum of 3 after applying the operations.</li>\n</ul>\n</div>\n\n<p>&nbsp;</p>\n<p><strong>Constraints:</strong></p>\n\n<ul>\n\t<li><code>1 &lt;= nums.length &lt;= 100</code></li>\n\t<li><code><font face=\"monospace\">0 &lt;= nums[i] &lt;= 10<sup>5</sup></font></code></li>\n\t<li><code>0 &lt;= k &lt;= 10<sup>5</sup></code></li>\n\t<li><code>0 &lt;= op1, op2 &lt;= nums.length</code></li>\n</ul>\n",
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"code": "class Solution(object):\n def minArraySum(self, nums, k, op1, op2):\n \"\"\"\n :type nums: List[int]\n :type k: int\n :type op1: int\n :type op2: int\n :rtype: int\n \"\"\"\n ",
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"code": "public class Solution {\n public int MinArraySum(int[] nums, int k, int op1, int op2) {\n \n }\n}",
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"code": "defmodule Solution do\n @spec min_array_sum(nums :: [integer], k :: integer, op1 :: integer, op2 :: integer) :: integer\n def min_array_sum(nums, k, op1, op2) do\n \n end\nend",
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"hints": [
"Think of dynamic programming with states to track progress and remaining operations.",
"Use <code>dp[index][op1][op2]</code> where each state tracks progress at <code>index</code> with <code>op1</code> and <code>op2</code> operations left.",
"At each state, try applying only operation 1, only operation 2, both in sequence, or skip both to find optimal results."
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