mirror of
https://gitee.com/coder-xiaomo/leetcode-problemset
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173 lines
17 KiB
JSON
173 lines
17 KiB
JSON
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"questionId": "2977",
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"questionFrontendId": "2828",
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"boundTopicId": null,
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"title": "Check if a String Is an Acronym of Words",
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"titleSlug": "check-if-a-string-is-an-acronym-of-words",
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"content": "<p>Given an array of strings <code>words</code> and a string <code>s</code>, determine if <code>s</code> is an <strong>acronym</strong> of words.</p>\n\n<p>The string <code>s</code> is considered an acronym of <code>words</code> if it can be formed by concatenating the <strong>first</strong> character of each string in <code>words</code> <strong>in order</strong>. For example, <code>"ab"</code> can be formed from <code>["apple", "banana"]</code>, but it can't be formed from <code>["bear", "aardvark"]</code>.</p>\n\n<p>Return <code>true</code><em> if </em><code>s</code><em> is an acronym of </em><code>words</code><em>, and </em><code>false</code><em> otherwise. </em></p>\n\n<p> </p>\n<p><strong class=\"example\">Example 1:</strong></p>\n\n<pre>\n<strong>Input:</strong> words = ["alice","bob","charlie"], s = "abc"\n<strong>Output:</strong> true\n<strong>Explanation:</strong> The first character in the words "alice", "bob", and "charlie" are 'a', 'b', and 'c', respectively. Hence, s = "abc" is the acronym. \n</pre>\n\n<p><strong class=\"example\">Example 2:</strong></p>\n\n<pre>\n<strong>Input:</strong> words = ["an","apple"], s = "a"\n<strong>Output:</strong> false\n<strong>Explanation:</strong> The first character in the words "an" and "apple" are 'a' and 'a', respectively. \nThe acronym formed by concatenating these characters is "aa". \nHence, s = "a" is not the acronym.\n</pre>\n\n<p><strong class=\"example\">Example 3:</strong></p>\n\n<pre>\n<strong>Input:</strong> words = ["never","gonna","give","up","on","you"], s = "ngguoy"\n<strong>Output:</strong> true\n<strong>Explanation: </strong>By concatenating the first character of the words in the array, we get the string "ngguoy". \nHence, s = "ngguoy" is the acronym.\n</pre>\n\n<p> </p>\n<p><strong>Constraints:</strong></p>\n\n<ul>\n\t<li><code>1 <= words.length <= 100</code></li>\n\t<li><code>1 <= words[i].length <= 10</code></li>\n\t<li><code>1 <= s.length <= 100</code></li>\n\t<li><code>words[i]</code> and <code>s</code> consist of lowercase English letters.</li>\n</ul>\n",
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"difficulty": "Easy",
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"exampleTestcases": "[\"alice\",\"bob\",\"charlie\"]\n\"abc\"\n[\"an\",\"apple\"]\n\"a\"\n[\"never\",\"gonna\",\"give\",\"up\",\"on\",\"you\"]\n\"ngguoy\"",
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"categoryTitle": "Algorithms",
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"code": "class Solution {\npublic:\n bool isAcronym(vector<string>& words, string s) {\n \n }\n};",
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"code": "class Solution {\n public boolean isAcronym(List<String> words, String s) {\n \n }\n}",
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"code": "class Solution(object):\n def isAcronym(self, words, s):\n \"\"\"\n :type words: List[str]\n :type s: str\n :rtype: bool\n \"\"\"\n ",
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"code": "public class Solution {\n public bool IsAcronym(IList<string> words, string s) {\n \n }\n}",
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"code": "class Solution {\n\n /**\n * @param String[] $words\n * @param String $s\n * @return Boolean\n */\n function isAcronym($words, $s) {\n \n }\n}",
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"code": "class Solution {\n fun isAcronym(words: List<String>, s: String): Boolean {\n \n }\n}",
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"code": "func isAcronym(words []string, s string) bool {\n \n}",
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"code": "# @param {String[]} words\n# @param {String} s\n# @return {Boolean}\ndef is_acronym(words, s)\n \nend",
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"code": "object Solution {\n def isAcronym(words: List[String], s: String): Boolean = {\n \n }\n}",
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"langSlug": "rust",
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"code": "impl Solution {\n pub fn is_acronym(words: Vec<String>, s: String) -> bool {\n \n }\n}",
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"code": "(define/contract (is-acronym words s)\n (-> (listof string?) string? boolean?)\n\n )",
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"code": "-spec is_acronym(Words :: [unicode:unicode_binary()], S :: unicode:unicode_binary()) -> boolean().\nis_acronym(Words, S) ->\n .",
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"code": "defmodule Solution do\n @spec is_acronym(words :: [String.t], s :: String.t) :: boolean\n def is_acronym(words, s) do\n\n end\nend",
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"<div class=\"_1l1MA\">Concatenate the first characters of the strings in <code>words</code>, and compare the resulting concatenation to <code>s</code>.</div>"
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],
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"solution": null,
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"sampleTestCase": "[\"alice\",\"bob\",\"charlie\"]\n\"abc\"",
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"metaData": "{\n \"name\": \"isAcronym\",\n \"params\": [\n {\n \"name\": \"words\",\n \"type\": \"list<string>\"\n },\n {\n \"type\": \"string\",\n \"name\": \"s\"\n }\n ],\n \"return\": {\n \"type\": \"boolean\"\n }\n}",
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