mirror of
https://gitee.com/coder-xiaomo/leetcode-problemset
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184 lines
26 KiB
JSON
184 lines
26 KiB
JSON
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"questionId": "3786",
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"categoryTitle": "Algorithms",
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"boundTopicId": 3590218,
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"title": "Longest Palindromic Subsequence After at Most K Operations",
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"content": "<p>You are given a string <code>s</code> and an integer <code>k</code>.</p>\n\n<p>In one operation, you can replace the character at any position with the next or previous letter in the alphabet (wrapping around so that <code>'a'</code> is after <code>'z'</code>). For example, replacing <code>'a'</code> with the next letter results in <code>'b'</code>, and replacing <code>'a'</code> with the previous letter results in <code>'z'</code>. Similarly, replacing <code>'z'</code> with the next letter results in <code>'a'</code>, and replacing <code>'z'</code> with the previous letter results in <code>'y'</code>.</p>\n\n<p>Return the length of the <strong>longest <span data-keyword=\"palindrome-string\">palindromic</span> <span data-keyword=\"subsequence-string-nonempty\">subsequence</span></strong> of <code>s</code> that can be obtained after performing <strong>at most</strong> <code>k</code> operations.</p>\n\n<p> </p>\n<p><strong class=\"example\">Example 1:</strong></p>\n\n<div class=\"example-block\">\n<p><strong>Input:</strong> <span class=\"example-io\">s = "abced", k = 2</span></p>\n\n<p><strong>Output:</strong> <span class=\"example-io\">3</span></p>\n\n<p><strong>Explanation:</strong></p>\n\n<ul>\n\t<li>Replace <code>s[1]</code> with the next letter, and <code>s</code> becomes <code>"acced"</code>.</li>\n\t<li>Replace <code>s[4]</code> with the previous letter, and <code>s</code> becomes <code>"accec"</code>.</li>\n</ul>\n\n<p>The subsequence <code>"ccc"</code> forms a palindrome of length 3, which is the maximum.</p>\n</div>\n\n<p><strong class=\"example\">Example 2:</strong></p>\n\n<div class=\"example-block\">\n<p><strong>Input:</strong> <span class=\"example-io\">s = "</span>aaazzz<span class=\"example-io\">", k = 4</span></p>\n\n<p><strong>Output:</strong> 6</p>\n\n<p><strong>Explanation:</strong></p>\n\n<ul>\n\t<li>Replace <code>s[0]</code> with the previous letter, and <code>s</code> becomes <code>"zaazzz"</code>.</li>\n\t<li>Replace <code>s[4]</code> with the next letter, and <code>s</code> becomes <code>"zaazaz"</code>.</li>\n\t<li>Replace <code>s[3]</code> with the next letter, and <code>s</code> becomes <code>"zaaaaz"</code>.</li>\n</ul>\n\n<p>The entire string forms a palindrome of length 6.</p>\n</div>\n\n<p> </p>\n<p><strong>Constraints:</strong></p>\n\n<ul>\n\t<li><code>1 <= s.length <= 200</code></li>\n\t<li><code>1 <= k <= 200</code></li>\n\t<li><code>s</code> consists of only lowercase English letters.</li>\n</ul>\n",
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"translatedTitle": "至多 K 次操作后的最长回文子序列",
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"translatedContent": "<p>给你一个字符串 <code>s</code> 和一个整数 <code>k</code>。</p>\n\n<p>在一次操作中,你可以将任意位置的字符替换为字母表中相邻的字符(字母表是循环的,因此 <code>'z'</code> 的下一个字母是 <code>'a'</code>)。例如,将 <code>'a'</code> 替换为下一个字母结果是 <code>'b'</code>,将 <code>'a'</code> 替换为上一个字母结果是 <code>'z'</code>;同样,将 <code>'z'</code> 替换为下一个字母结果是 <code>'a'</code>,替换为上一个字母结果是 <code>'y'</code>。</p>\n\n<p>返回在进行 <strong>最多</strong> <code>k</code> 次操作后,<code>s</code> 的 <strong>最长回文子序列 </strong>的长度。</p>\n\n<p><strong>子序列 </strong>是一个 <strong>非空 </strong>字符串,可以通过删除原字符串中的某些字符(或不删除任何字符)并保持剩余字符的相对顺序得到。</p>\n\n<p><strong>回文 </strong>是正着读和反着读都相同的字符串。</p>\n\n<p> </p>\n\n<p><strong class=\"example\">示例 1:</strong></p>\n\n<div class=\"example-block\">\n<p><strong>输入:</strong> <span class=\"example-io\">s = \"abced\", k = 2</span></p>\n\n<p><strong>输出:</strong> <span class=\"example-io\">3</span></p>\n\n<p><strong>解释:</strong></p>\n\n<ul>\n\t<li>将 <code>s[1]</code> 替换为下一个字母,得到 <code>\"acced\"</code>。</li>\n\t<li>将 <code>s[4]</code> 替换为上一个字母,得到 <code>\"accec\"</code>。</li>\n</ul>\n\n<p>子序列 <code>\"ccc\"</code> 形成一个长度为 3 的回文,这是最长的回文子序列。</p>\n</div>\n\n<p><strong class=\"example\">示例 2:</strong></p>\n\n<div class=\"example-block\">\n<p><strong>输入:</strong> <span class=\"example-io\">s = \"aaazzz\", k = 4</span></p>\n\n<p><strong>输出:</strong> 6</p>\n\n<p><strong>解释:</strong></p>\n\n<ul>\n\t<li>将 <code>s[0]</code> 替换为上一个字母,得到 <code>\"zaazzz\"</code>。</li>\n\t<li>将 <code>s[4]</code> 替换为下一个字母,得到 <code>\"zaazaz\"</code>。</li>\n\t<li>将 <code>s[3]</code> 替换为下一个字母,得到 <code>\"zaaaaz\"</code>。</li>\n</ul>\n\n<p>整个字符串形成一个长度为 6 的回文。</p>\n</div>\n\n<p> </p>\n\n<p><strong>提示:</strong></p>\n\n<ul>\n\t<li><code>1 <= s.length <= 200</code></li>\n\t<li><code>1 <= k <= 200</code></li>\n\t<li><code>s</code> 仅由小写英文字母组成。</li>\n</ul>\n",
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"Use dynamic programming.",
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"<code>dp[i][j][k]</code> is the length of the longest palindromic subsequence in substring <code>[i..j]</code> with cost at most <code>k</code>.",
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"<code>dp[i][j][k] = max(dp[i + 1][j][k], dp[i][j - 1][k], dp[i + 1][j - 1][k - dist(s[i], s[j])] + 2)</code>, where <code>dist(x, y)</code> is the minimum cyclic distance between <code>x</code> and <code>y</code>."
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