leetcode-problemset/leetcode-cn/originData/employee-importance.json

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            "title": "Employee Importance",
            "titleSlug": "employee-importance",
            "content": "<p>You have a data structure of employee information, including the employee&#39;s unique ID, importance value, and direct subordinates&#39; IDs.</p>\n\n<p>You are given an array of employees <code>employees</code> where:</p>\n\n<ul>\n\t<li><code>employees[i].id</code> is the ID of the <code>i<sup>th</sup></code> employee.</li>\n\t<li><code>employees[i].importance</code> is the importance value of the <code>i<sup>th</sup></code> employee.</li>\n\t<li><code>employees[i].subordinates</code> is a list of the IDs of the direct subordinates of the <code>i<sup>th</sup></code> employee.</li>\n</ul>\n\n<p>Given an integer <code>id</code> that represents an employee&#39;s ID, return <em>the <strong>total</strong> importance value of this employee and all their direct and indirect subordinates</em>.</p>\n\n<p>&nbsp;</p>\n<p><strong class=\"example\">Example 1:</strong></p>\n<img alt=\"\" src=\"https://assets.leetcode.com/uploads/2021/05/31/emp1-tree.jpg\" style=\"width: 400px; height: 258px;\" />\n<pre>\n<strong>Input:</strong> employees = [[1,5,[2,3]],[2,3,[]],[3,3,[]]], id = 1\n<strong>Output:</strong> 11\n<strong>Explanation:</strong> Employee 1 has an importance value of 5 and has two direct subordinates: employee 2 and employee 3.\nThey both have an importance value of 3.\nThus, the total importance value of employee 1 is 5 + 3 + 3 = 11.\n</pre>\n\n<p><strong class=\"example\">Example 2:</strong></p>\n<img alt=\"\" src=\"https://assets.leetcode.com/uploads/2021/05/31/emp2-tree.jpg\" style=\"width: 362px; height: 361px;\" />\n<pre>\n<strong>Input:</strong> employees = [[1,2,[5]],[5,-3,[]]], id = 5\n<strong>Output:</strong> -3\n<strong>Explanation:</strong> Employee 5 has an importance value of -3 and has no direct subordinates.\nThus, the total importance value of employee 5 is -3.\n</pre>\n\n<p>&nbsp;</p>\n<p><strong>Constraints:</strong></p>\n\n<ul>\n\t<li><code>1 &lt;= employees.length &lt;= 2000</code></li>\n\t<li><code>1 &lt;= employees[i].id &lt;= 2000</code></li>\n\t<li>All <code>employees[i].id</code> are <strong>unique</strong>.</li>\n\t<li><code>-100 &lt;= employees[i].importance &lt;= 100</code></li>\n\t<li>One employee has at most one direct leader and may have several subordinates.</li>\n\t<li>The IDs in <code>employees[i].subordinates</code> are valid IDs.</li>\n</ul>\n",
            "translatedTitle": "员工的重要性",
            "translatedContent": "<p>你有一个保存员工信息的数据结构，它包含了员工唯一的 id ，重要度和直系下属的 id 。</p>\n\n<p>给定一个员工数组&nbsp;<code>employees</code>，其中：</p>\n\n<ul>\n\t<li><code>employees[i].id</code> 是第&nbsp;<code>i</code>&nbsp;个员工的 ID。</li>\n\t<li><code>employees[i].importance</code>&nbsp;是第&nbsp;<code>i</code>&nbsp;个员工的重要度。</li>\n\t<li><code>employees[i].subordinates</code> 是第 <code>i</code> 名员工的直接下属的 ID 列表。</li>\n</ul>\n\n<p>给定一个整数&nbsp;<code>id</code>&nbsp;表示一个员工的 ID，返回这个员工和他所有下属的重要度的 <strong>总和</strong>。</p>\n\n<p>&nbsp;</p>\n\n<p><strong>示例 1：</strong></p>\n\n<p><strong><img alt=\"\" src=\"https://pic.leetcode.cn/1716170448-dKZffb-image.png\" style=\"width: 400px; height: 258px;\" /></strong></p>\n\n<pre>\n<strong>输入：</strong>employees = [[1,5,[2,3]],[2,3,[]],[3,3,[]]], id = 1\n<strong>输出：</strong>11\n<strong>解释：</strong>\n员工 1 自身的重要度是 5 ，他有两个直系下属 2 和 3 ，而且 2 和 3 的重要度均为 3 。因此员工 1 的总重要度是 5 + 3 + 3 = 11 。\n</pre>\n\n<p>&nbsp;</p>\n\n<p><strong>示例 2：</strong></p>\n\n<p><strong><img alt=\"\" src=\"https://pic.leetcode.cn/1716170929-dkWpra-image.png\" style=\"width: 362px; height: 361px;\" /></strong></p>\n\n<pre>\n<strong>输入：</strong>employees = [[1,2,[5]],[5,-3,[]]], id = 5\n<strong>输出：</strong>-3\n<strong>解释：</strong>员工 5 的重要度为 -3 并且没有直接下属。\n因此，员工 5 的总重要度为 -3。\n</pre>\n\n<p>&nbsp;</p>\n\n<p><strong>提示：</strong></p>\n\n<ul>\n\t<li><code>1 &lt;= employees.length &lt;= 2000</code></li>\n\t<li><code>1 &lt;= employees[i].id &lt;= 2000</code></li>\n\t<li>所有的&nbsp;<code>employees[i].id</code>&nbsp;<strong>互不相同</strong>。</li>\n\t<li><code>-100 &lt;= employees[i].importance &lt;= 100</code></li>\n\t<li>一名员工最多有一名直接领导，并可能有多名下属。</li>\n\t<li><code>employees[i].subordinates</code>&nbsp;中的 ID 都有效。</li>\n</ul>\n",
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