leetcode-problemset/leetcode-cn/originData/closest-prime-numbers-in-range.json

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            "title": "Closest Prime Numbers in Range",
            "titleSlug": "closest-prime-numbers-in-range",
            "content": "<p>Given two positive integers <code>left</code> and <code>right</code>, find the two integers <code>num1</code> and <code>num2</code> such that:</p>\n\n<ul>\n\t<li><code>left &lt;= num1 &lt; num2 &lt;= right </code>.</li>\n\t<li><code>num1</code> and <code>num2</code> are both <strong>prime</strong> numbers.</li>\n\t<li><code>num2 - num1</code> is the <strong>minimum</strong> amongst all other pairs satisfying the above conditions.</li>\n</ul>\n\n<p>Return <em>the positive integer array</em> <code>ans = [num1, num2]</code>. <em>If there are multiple pairs satisfying these conditions, return the one with the minimum</em> <code>num1</code> <em>value or</em> <code>[-1, -1]</code> <em>if such numbers do not exist.</em></p>\n\n<p>A number greater than <code>1</code> is called <b>prime</b> if it is only divisible by <code>1</code> and itself.</p>\n\n<p>&nbsp;</p>\n<p><strong class=\"example\">Example 1:</strong></p>\n\n<pre>\n<strong>Input:</strong> left = 10, right = 19\n<strong>Output:</strong> [11,13]\n<strong>Explanation:</strong> The prime numbers between 10 and 19 are 11, 13, 17, and 19.\nThe closest gap between any pair is 2, which can be achieved by [11,13] or [17,19].\nSince 11 is smaller than 17, we return the first pair.\n</pre>\n\n<p><strong class=\"example\">Example 2:</strong></p>\n\n<pre>\n<strong>Input:</strong> left = 4, right = 6\n<strong>Output:</strong> [-1,-1]\n<strong>Explanation:</strong> There exists only one prime number in the given range, so the conditions cannot be satisfied.\n</pre>\n\n<p>&nbsp;</p>\n<p><strong>Constraints:</strong></p>\n\n<ul>\n\t<li><code>1 &lt;= left &lt;= right &lt;= 10<sup>6</sup></code></li>\n</ul>\n\n<p>&nbsp;</p>\n<style type=\"text/css\">.spoilerbutton {display:block; border:dashed; padding: 0px 0px; margin:10px 0px; font-size:150%; font-weight: bold; color:#000000; background-color:cyan; outline:0; \n}\n.spoiler {overflow:hidden;}\n.spoiler > div {-webkit-transition: all 0s ease;-moz-transition: margin 0s ease;-o-transition: all 0s ease;transition: margin 0s ease;}\n.spoilerbutton[value=\"Show Message\"] + .spoiler > div {margin-top:-500%;}\n.spoilerbutton[value=\"Hide Message\"] + .spoiler {padding:5px;}\n</style>\n",
            "translatedTitle": "范围内最接近的两个质数",
            "translatedContent": "<p>给你两个正整数&nbsp;<code>left</code> 和&nbsp;<code>right</code>&nbsp;，请你找到两个整数&nbsp;<code>num1</code> 和&nbsp;<code>num2</code>&nbsp;，它们满足：</p>\n\n<ul>\n\t<li><code>left &lt;= nums1 &lt; nums2 &lt;= right&nbsp;</code>&nbsp;。</li>\n\t<li><code>nums1</code> 和&nbsp;<code>nums2</code>&nbsp;都是 <strong>质数</strong>&nbsp;。</li>\n\t<li><code>nums2 - nums1</code>&nbsp;是满足上述条件的质数对中的 <strong>最小值</strong>&nbsp;。</li>\n</ul>\n\n<p>请你返回正整数数组&nbsp;<code>ans = [nums1, nums2]</code>&nbsp;。如果有多个整数对满足上述条件，请你返回&nbsp;<code>nums1</code>&nbsp;最小的质数对。如果不存在符合题意的质数对，请你返回&nbsp;<code>[-1, -1]</code>&nbsp;。</p>\n\n<p>如果一个整数大于&nbsp;<code>1</code>&nbsp;，且只能被&nbsp;<code>1</code> 和它自己整除，那么它是一个 <strong>质数</strong>。</p>\n\n<p>&nbsp;</p>\n\n<p><strong>示例 1：</strong></p>\n\n<pre>\n<b>输入：</b>left = 10, right = 19\n<b>输出：</b>[11,13]\n<b>解释：</b>10 到 19 之间的质数为 11 ，13 ，17 和 19 。\n质数对的最小差值是 2 ，[11,13] 和 [17,19] 都可以得到最小差值。\n由于 11 比 17 小，我们返回第一个质数对。\n</pre>\n\n<p><strong>示例 2：</strong></p>\n\n<pre>\n<b>输入：</b>left = 4, right = 6\n<b>输出：</b>[-1,-1]\n<b>解释：</b>给定范围内只有一个质数，所以题目条件无法被满足。\n</pre>\n\n<p>&nbsp;</p>\n\n<p><strong>提示：</strong></p>\n\n<ul>\n\t<li><code>1 &lt;= left &lt;= right &lt;= 10<sup>6</sup></code></li>\n</ul>\n",
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                "Use Sieve of Eratosthenes to mark numbers that are primes.",
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