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leetcode-problemset/leetcode/problem/add-digits.html

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<p>Given an integer <code>num</code>, repeatedly add all its digits until the result has only one digit, and return it.</p>
<p>&nbsp;</p>
<p><strong class="example">Example 1:</strong></p>
<pre>
<strong>Input:</strong> num = 38
<strong>Output:</strong> 2
<strong>Explanation:</strong> The process is
38 --&gt; 3 + 8 --&gt; 11
11 --&gt; 1 + 1 --&gt; 2
Since 2 has only one digit, return it.
</pre>
<p><strong class="example">Example 2:</strong></p>
<pre>
<strong>Input:</strong> num = 0
<strong>Output:</strong> 0
</pre>
<p>&nbsp;</p>
<p><strong>Constraints:</strong></p>
<ul>
<li><code>0 &lt;= num &lt;= 2<sup>31</sup> - 1</code></li>
</ul>
<p>&nbsp;</p>
<p><strong>Follow up:</strong> Could you do it without any loop/recursion in <code>O(1)</code> runtime?</p>