mirror of
https://gitee.com/coder-xiaomo/leetcode-problemset
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181 lines
17 KiB
JSON
181 lines
17 KiB
JSON
{
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"questionId": "2599",
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"boundTopicId": null,
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"title": "Take K of Each Character From Left and Right",
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"titleSlug": "take-k-of-each-character-from-left-and-right",
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"content": "<p>You are given a string <code>s</code> consisting of the characters <code>'a'</code>, <code>'b'</code>, and <code>'c'</code> and a non-negative integer <code>k</code>. Each minute, you may take either the <strong>leftmost</strong> character of <code>s</code>, or the <strong>rightmost</strong> character of <code>s</code>.</p>\n\n<p>Return<em> the <strong>minimum</strong> number of minutes needed for you to take <strong>at least</strong> </em><code>k</code><em> of each character, or return </em><code>-1</code><em> if it is not possible to take </em><code>k</code><em> of each character.</em></p>\n\n<p> </p>\n<p><strong class=\"example\">Example 1:</strong></p>\n\n<pre>\n<strong>Input:</strong> s = "aabaaaacaabc", k = 2\n<strong>Output:</strong> 8\n<strong>Explanation:</strong> \nTake three characters from the left of s. You now have two 'a' characters, and one 'b' character.\nTake five characters from the right of s. You now have four 'a' characters, two 'b' characters, and two 'c' characters.\nA total of 3 + 5 = 8 minutes is needed.\nIt can be proven that 8 is the minimum number of minutes needed.\n</pre>\n\n<p><strong class=\"example\">Example 2:</strong></p>\n\n<pre>\n<strong>Input:</strong> s = "a", k = 1\n<strong>Output:</strong> -1\n<strong>Explanation:</strong> It is not possible to take one 'b' or 'c' so return -1.\n</pre>\n\n<p> </p>\n<p><strong>Constraints:</strong></p>\n\n<ul>\n\t<li><code>1 <= s.length <= 10<sup>5</sup></code></li>\n\t<li><code>s</code> consists of only the letters <code>'a'</code>, <code>'b'</code>, and <code>'c'</code>.</li>\n\t<li><code>0 <= k <= s.length</code></li>\n</ul>\n",
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"difficulty": "Medium",
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"exampleTestcases": "\"aabaaaacaabc\"\n2\n\"a\"\n1",
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"categoryTitle": "Algorithms",
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"code": "class Solution(object):\n def takeCharacters(self, s, k):\n \"\"\"\n :type s: str\n :type k: int\n :rtype: int\n \"\"\"\n ",
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"code": "# @param {String} s\n# @param {Integer} k\n# @return {Integer}\ndef take_characters(s, k)\n \nend",
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"code": "object Solution {\n def takeCharacters(s: String, k: Int): Int = {\n \n }\n}",
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"lang": "Rust",
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"code": "impl Solution {\n pub fn take_characters(s: String, k: i32) -> i32 {\n \n }\n}",
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"code": "(define/contract (take-characters s k)\n (-> string? exact-integer? exact-integer?)\n )",
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"lang": "Erlang",
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"langSlug": "erlang",
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"code": "-spec take_characters(S :: unicode:unicode_binary(), K :: integer()) -> integer().\ntake_characters(S, K) ->\n .",
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"code": "defmodule Solution do\n @spec take_characters(s :: String.t, k :: integer) :: integer\n def take_characters(s, k) do\n \n end\nend",
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"stats": "{\"totalAccepted\": \"13.8K\", \"totalSubmission\": \"40.4K\", \"totalAcceptedRaw\": 13817, \"totalSubmissionRaw\": 40431, \"acRate\": \"34.2%\"}",
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"hints": [
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"Start by counting the frequency of each character and checking if it is possible.",
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"If you take x characters from the left side, what is the minimum number of characters you need to take from the right side? Find this for all values of x in the range 0 ≤ x ≤ s.length.",
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"Use a two-pointers approach to avoid computing the same information multiple times."
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],
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"solution": null,
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"status": null,
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"sampleTestCase": "\"aabaaaacaabc\"\n2",
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"metaData": "{\n \"name\": \"takeCharacters\",\n \"params\": [\n {\n \"name\": \"s\",\n \"type\": \"string\"\n },\n {\n \"type\": \"integer\",\n \"name\": \"k\"\n }\n ],\n \"return\": {\n \"type\": \"integer\"\n }\n}",
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If you need more libraries, you can import it yourself.</p>\\r\\n\\r\\n<p>For Map/TreeMap data structure, you may use <a href=\\\"http://www.grantjenks.com/docs/sortedcontainers/\\\" target=\\\"_blank\\\">sortedcontainers</a> library.</p>\\r\\n\\r\\n<p>Note that Python 2.7 <a href=\\\"https://www.python.org/dev/peps/pep-0373/\\\" target=\\\"_blank\\\">will not be maintained past 2020</a>. 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