mirror of
https://gitee.com/coder-xiaomo/leetcode-problemset
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175 lines
18 KiB
JSON
175 lines
18 KiB
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"title": "Sum of Matrix After Queries",
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"content": "<p>You are given an integer <code>n</code> and a <strong>0-indexed</strong> <strong>2D array</strong> <code>queries</code> where <code>queries[i] = [type<sub>i</sub>, index<sub>i</sub>, val<sub>i</sub>]</code>.</p>\n\n<p>Initially, there is a <strong>0-indexed</strong> <code>n x n</code> matrix filled with <code>0</code>'s. For each query, you must apply one of the following changes:</p>\n\n<ul>\n\t<li>if <code>type<sub>i</sub> == 0</code>, set the values in the row with <code>index<sub>i</sub></code> to <code>val<sub>i</sub></code>, overwriting any previous values.</li>\n\t<li>if <code>type<sub>i</sub> == 1</code>, set the values in the column with <code>index<sub>i</sub></code> to <code>val<sub>i</sub></code>, overwriting any previous values.</li>\n</ul>\n\n<p>Return <em>the sum of integers in the matrix after all queries are applied</em>.</p>\n\n<p> </p>\n<p><strong class=\"example\">Example 1:</strong></p>\n<img alt=\"\" src=\"https://assets.leetcode.com/uploads/2023/05/11/exm1.png\" style=\"width: 681px; height: 161px;\" />\n<pre>\n<strong>Input:</strong> n = 3, queries = [[0,0,1],[1,2,2],[0,2,3],[1,0,4]]\n<strong>Output:</strong> 23\n<strong>Explanation:</strong> The image above describes the matrix after each query. The sum of the matrix after all queries are applied is 23. \n</pre>\n\n<p><strong class=\"example\">Example 2:</strong></p>\n<img alt=\"\" src=\"https://assets.leetcode.com/uploads/2023/05/11/exm2.png\" style=\"width: 681px; height: 331px;\" />\n<pre>\n<strong>Input:</strong> n = 3, queries = [[0,0,4],[0,1,2],[1,0,1],[0,2,3],[1,2,1]]\n<strong>Output:</strong> 17\n<strong>Explanation:</strong> The image above describes the matrix after each query. The sum of the matrix after all queries are applied is 17.\n</pre>\n\n<p> </p>\n<p><strong>Constraints:</strong></p>\n\n<ul>\n\t<li><code>1 <= n <= 10<sup>4</sup></code></li>\n\t<li><code>1 <= queries.length <= 5 * 10<sup>4</sup></code></li>\n\t<li><code>queries[i].length == 3</code></li>\n\t<li><code>0 <= type<sub>i</sub> <= 1</code></li>\n\t<li><code>0 <= index<sub>i</sub> < n</code></li>\n\t<li><code>0 <= val<sub>i</sub> <= 10<sup>5</sup></code></li>\n</ul>\n",
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"Process queries in reversed order, as the latest queries represent the most recent changes in the matrix.",
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"Once you encounter an operation on some row/column, no further operations will affect the values in this row/column. Keep track of seen rows and columns with a set.",
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"When operating on an unseen row/column, the number of affected cells is the number of columns/rows you haven’t previously seen."
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