mirror of
https://gitee.com/coder-xiaomo/leetcode-problemset
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214 lines
20 KiB
JSON
214 lines
20 KiB
JSON
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"questionId": "3557",
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"title": "Minimum Number of Valid Strings to Form Target II",
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"content": "<p>You are given an array of strings <code>words</code> and a string <code>target</code>.</p>\n\n<p>A string <code>x</code> is called <strong>valid</strong> if <code>x</code> is a <span data-keyword=\"string-prefix\">prefix</span> of <strong>any</strong> string in <code>words</code>.</p>\n\n<p>Return the <strong>minimum</strong> number of <strong>valid</strong> strings that can be <em>concatenated</em> to form <code>target</code>. If it is <strong>not</strong> possible to form <code>target</code>, return <code>-1</code>.</p>\n\n<p> </p>\n<p><strong class=\"example\">Example 1:</strong></p>\n\n<div class=\"example-block\">\n<p><strong>Input:</strong> <span class=\"example-io\">words = ["abc","aaaaa","bcdef"], target = "aabcdabc"</span></p>\n\n<p><strong>Output:</strong> <span class=\"example-io\">3</span></p>\n\n<p><strong>Explanation:</strong></p>\n\n<p>The target string can be formed by concatenating:</p>\n\n<ul>\n\t<li>Prefix of length 2 of <code>words[1]</code>, i.e. <code>"aa"</code>.</li>\n\t<li>Prefix of length 3 of <code>words[2]</code>, i.e. <code>"bcd"</code>.</li>\n\t<li>Prefix of length 3 of <code>words[0]</code>, i.e. <code>"abc"</code>.</li>\n</ul>\n</div>\n\n<p><strong class=\"example\">Example 2:</strong></p>\n\n<div class=\"example-block\">\n<p><strong>Input:</strong> <span class=\"example-io\">words = ["abababab","ab"], target = "ababaababa"</span></p>\n\n<p><strong>Output:</strong> <span class=\"example-io\">2</span></p>\n\n<p><strong>Explanation:</strong></p>\n\n<p>The target string can be formed by concatenating:</p>\n\n<ul>\n\t<li>Prefix of length 5 of <code>words[0]</code>, i.e. <code>"ababa"</code>.</li>\n\t<li>Prefix of length 5 of <code>words[0]</code>, i.e. <code>"ababa"</code>.</li>\n</ul>\n</div>\n\n<p><strong class=\"example\">Example 3:</strong></p>\n\n<div class=\"example-block\">\n<p><strong>Input:</strong> <span class=\"example-io\">words = ["abcdef"], target = "xyz"</span></p>\n\n<p><strong>Output:</strong> <span class=\"example-io\">-1</span></p>\n</div>\n\n<p> </p>\n<p><strong>Constraints:</strong></p>\n\n<ul>\n\t<li><code>1 <= words.length <= 100</code></li>\n\t<li><code>1 <= words[i].length <= 5 * 10<sup>4</sup></code></li>\n\t<li>The input is generated such that <code>sum(words[i].length) <= 10<sup>5</sup></code>.</li>\n\t<li><code>words[i]</code> consists only of lowercase English letters.</li>\n\t<li><code>1 <= target.length <= 5 * 10<sup>4</sup></code></li>\n\t<li><code>target</code> consists only of lowercase English letters.</li>\n</ul>\n",
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"difficulty": "Hard",
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"exampleTestcases": "[\"abc\",\"aaaaa\",\"bcdef\"]\n\"aabcdabc\"\n[\"abababab\",\"ab\"]\n\"ababaababa\"\n[\"abcdef\"]\n\"xyz\"",
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"Let <code>dp[i]</code> be the minimum cost to form the prefix of length <code>i</code> of <code>target</code>.",
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"Use Rabin-Karp to hash every prefix and store it in a HashSet.",
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"Use Binary search to find the longest substring starting at index <code>i</code> (<code>target[i..j]</code>) that has a hash present in the HashSet.",
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"Inverse Modulo precomputation can optimise hash calculation.",
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"Use Lazy Segment Tree, or basic Segment Tree to update <code>dp[i..j]</code>.",
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"Is it possible to use two TreeSets to update <code>dp[i..j]</code>?"
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