mirror of
https://gitee.com/coder-xiaomo/leetcode-problemset
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174 lines
19 KiB
JSON
174 lines
19 KiB
JSON
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"title": "Minimum Hours of Training to Win a Competition",
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"content": "<p>You are entering a competition, and are given two <strong>positive</strong> integers <code>initialEnergy</code> and <code>initialExperience</code> denoting your initial energy and initial experience respectively.</p>\n\n<p>You are also given two <strong>0-indexed</strong> integer arrays <code>energy</code> and <code>experience</code>, both of length <code>n</code>.</p>\n\n<p>You will face <code>n</code> opponents <strong>in order</strong>. The energy and experience of the <code>i<sup>th</sup></code> opponent is denoted by <code>energy[i]</code> and <code>experience[i]</code> respectively. When you face an opponent, you need to have both <strong>strictly</strong> greater experience and energy to defeat them and move to the next opponent if available.</p>\n\n<p>Defeating the <code>i<sup>th</sup></code> opponent <strong>increases</strong> your experience by <code>experience[i]</code>, but <strong>decreases</strong> your energy by <code>energy[i]</code>.</p>\n\n<p>Before starting the competition, you can train for some number of hours. After each hour of training, you can <strong>either</strong> choose to increase your initial experience by one, or increase your initial energy by one.</p>\n\n<p>Return <em>the <strong>minimum</strong> number of training hours required to defeat all </em><code>n</code><em> opponents</em>.</p>\n\n<p> </p>\n<p><strong class=\"example\">Example 1:</strong></p>\n\n<pre>\n<strong>Input:</strong> initialEnergy = 5, initialExperience = 3, energy = [1,4,3,2], experience = [2,6,3,1]\n<strong>Output:</strong> 8\n<strong>Explanation:</strong> You can increase your energy to 11 after 6 hours of training, and your experience to 5 after 2 hours of training.\nYou face the opponents in the following order:\n- You have more energy and experience than the 0<sup>th</sup> opponent so you win.\n Your energy becomes 11 - 1 = 10, and your experience becomes 5 + 2 = 7.\n- You have more energy and experience than the 1<sup>st</sup> opponent so you win.\n Your energy becomes 10 - 4 = 6, and your experience becomes 7 + 6 = 13.\n- You have more energy and experience than the 2<sup>nd</sup> opponent so you win.\n Your energy becomes 6 - 3 = 3, and your experience becomes 13 + 3 = 16.\n- You have more energy and experience than the 3<sup>rd</sup> opponent so you win.\n Your energy becomes 3 - 2 = 1, and your experience becomes 16 + 1 = 17.\nYou did a total of 6 + 2 = 8 hours of training before the competition, so we return 8.\nIt can be proven that no smaller answer exists.\n</pre>\n\n<p><strong class=\"example\">Example 2:</strong></p>\n\n<pre>\n<strong>Input:</strong> initialEnergy = 2, initialExperience = 4, energy = [1], experience = [3]\n<strong>Output:</strong> 0\n<strong>Explanation:</strong> You do not need any additional energy or experience to win the competition, so we return 0.\n</pre>\n\n<p> </p>\n<p><strong>Constraints:</strong></p>\n\n<ul>\n\t<li><code>n == energy.length == experience.length</code></li>\n\t<li><code>1 <= n <= 100</code></li>\n\t<li><code>1 <= initialEnergy, initialExperience, energy[i], experience[i] <= 100</code></li>\n</ul>\n",
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"code": "# @param {Integer} initial_energy\n# @param {Integer} initial_experience\n# @param {Integer[]} energy\n# @param {Integer[]} experience\n# @return {Integer}\ndef min_number_of_hours(initial_energy, initial_experience, energy, experience)\n \nend",
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"code": "impl Solution {\n pub fn min_number_of_hours(initial_energy: i32, initial_experience: i32, energy: Vec<i32>, experience: Vec<i32>) -> i32 {\n \n }\n}",
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"Find the minimum number of training hours needed for the energy and experience separately, and sum the results.",
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"Try to increase the energy and experience until you find how much is enough to win the competition."
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