leetcode-problemset/leetcode/originData/maximum-number-of-weeks-for-which-you-can-work.json

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            "title": "Maximum Number of Weeks for Which You Can Work",
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            "content": "<p>There are <code>n</code> projects numbered from <code>0</code> to <code>n - 1</code>. You are given an integer array <code>milestones</code> where each <code>milestones[i]</code> denotes the number of milestones the <code>i<sup>th</sup></code> project has.</p>\n\n<p>You can work on the projects following these two rules:</p>\n\n<ul>\n\t<li>Every week, you will finish <strong>exactly one</strong> milestone of <strong>one</strong> project. You&nbsp;<strong>must</strong>&nbsp;work every week.</li>\n\t<li>You <strong>cannot</strong> work on two milestones from the same project for two <strong>consecutive</strong> weeks.</li>\n</ul>\n\n<p>Once all the milestones of all the projects are finished, or if the only milestones that you can work on will cause you to violate the above rules, you will <strong>stop working</strong>. Note that you may not be able to finish every project&#39;s milestones due to these constraints.</p>\n\n<p>Return <em>the <strong>maximum</strong> number of weeks you would be able to work on the projects without violating the rules mentioned above</em>.</p>\n\n<p>&nbsp;</p>\n<p><strong class=\"example\">Example 1:</strong></p>\n\n<pre>\n<strong>Input:</strong> milestones = [1,2,3]\n<strong>Output:</strong> 6\n<strong>Explanation:</strong> One possible scenario is:\n​​​​- During the 1<sup>st</sup> week, you will work on a milestone of project 0.\n- During the 2<sup>nd</sup> week, you will work on a milestone of project 2.\n- During the 3<sup>rd</sup> week, you will work on a milestone of project 1.\n- During the 4<sup>th</sup> week, you will work on a milestone of project 2.\n- During the 5<sup>th</sup> week, you will work on a milestone of project 1.\n- During the 6<sup>th</sup> week, you will work on a milestone of project 2.\nThe total number of weeks is 6.\n</pre>\n\n<p><strong class=\"example\">Example 2:</strong></p>\n\n<pre>\n<strong>Input:</strong> milestones = [5,2,1]\n<strong>Output:</strong> 7\n<strong>Explanation:</strong> One possible scenario is:\n- During the 1<sup>st</sup> week, you will work on a milestone of project 0.\n- During the 2<sup>nd</sup> week, you will work on a milestone of project 1.\n- During the 3<sup>rd</sup> week, you will work on a milestone of project 0.\n- During the 4<sup>th</sup> week, you will work on a milestone of project 1.\n- During the 5<sup>th</sup> week, you will work on a milestone of project 0.\n- During the 6<sup>th</sup> week, you will work on a milestone of project 2.\n- During the 7<sup>th</sup> week, you will work on a milestone of project 0.\nThe total number of weeks is 7.\nNote that you cannot work on the last milestone of project 0 on 8<sup>th</sup> week because it would violate the rules.\nThus, one milestone in project 0 will remain unfinished.\n</pre>\n\n<p>&nbsp;</p>\n<p><strong>Constraints:</strong></p>\n\n<ul>\n\t<li><code>n == milestones.length</code></li>\n\t<li><code>1 &lt;= n &lt;= 10<sup>5</sup></code></li>\n\t<li><code>1 &lt;= milestones[i] &lt;= 10<sup>9</sup></code></li>\n</ul>\n",
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                    "code": "class Solution {\n\n    /**\n     * @param Integer[] $milestones\n     * @return Integer\n     */\n    function numberOfWeeks($milestones) {\n        \n    }\n}",
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