leetcode-problemset/leetcode/originData/maximize-happiness-of-selected-children.json

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            "title": "Maximize Happiness of Selected Children",
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            "content": "<p>You are given an array <code>happiness</code> of length <code>n</code>, and a <strong>positive</strong> integer <code>k</code>.</p>\n\n<p>There are <code>n</code> children standing in a queue, where the <code>i<sup>th</sup></code> child has <strong>happiness value</strong> <code>happiness[i]</code>. You want to select <code>k</code> children from these <code>n</code> children in <code>k</code> turns.</p>\n\n<p>In each turn, when you select a child, the <strong>happiness value</strong> of all the children that have <strong>not</strong> been selected till now decreases by <code>1</code>. Note that the happiness value <strong>cannot</strong> become negative and gets decremented <strong>only</strong> if it is positive.</p>\n\n<p>Return <em>the <strong>maximum</strong> sum of the happiness values of the selected children you can achieve by selecting </em><code>k</code> <em>children</em>.</p>\n\n<p>&nbsp;</p>\n<p><strong class=\"example\">Example 1:</strong></p>\n\n<pre>\n<strong>Input:</strong> happiness = [1,2,3], k = 2\n<strong>Output:</strong> 4\n<strong>Explanation:</strong> We can pick 2 children in the following way:\n- Pick the child with the happiness value == 3. The happiness value of the remaining children becomes [0,1].\n- Pick the child with the happiness value == 1. The happiness value of the remaining child becomes [0]. Note that the happiness value cannot become less than 0.\nThe sum of the happiness values of the selected children is 3 + 1 = 4.\n</pre>\n\n<p><strong class=\"example\">Example 2:</strong></p>\n\n<pre>\n<strong>Input:</strong> happiness = [1,1,1,1], k = 2\n<strong>Output:</strong> 1\n<strong>Explanation:</strong> We can pick 2 children in the following way:\n- Pick any child with the happiness value == 1. The happiness value of the remaining children becomes [0,0,0].\n- Pick the child with the happiness value == 0. The happiness value of the remaining child becomes [0,0].\nThe sum of the happiness values of the selected children is 1 + 0 = 1.\n</pre>\n\n<p><strong class=\"example\">Example 3:</strong></p>\n\n<pre>\n<strong>Input:</strong> happiness = [2,3,4,5], k = 1\n<strong>Output:</strong> 5\n<strong>Explanation:</strong> We can pick 1 child in the following way:\n- Pick the child with the happiness value == 5. The happiness value of the remaining children becomes [1,2,3].\nThe sum of the happiness values of the selected children is 5.\n</pre>\n\n<p>&nbsp;</p>\n<p><strong>Constraints:</strong></p>\n\n<ul>\n\t<li><code>1 &lt;= n == happiness.length &lt;= 2 * 10<sup>5</sup></code></li>\n\t<li><code>1 &lt;= happiness[i] &lt;= 10<sup>8</sup></code></li>\n\t<li><code>1 &lt;= k &lt;= n</code></li>\n</ul>\n",
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                    "code": "class Solution(object):\n    def maximumHappinessSum(self, happiness, k):\n        \"\"\"\n        :type happiness: List[int]\n        :type k: int\n        :rtype: int\n        \"\"\"\n        ",
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                    "code": "/**\n * @param {number[]} happiness\n * @param {number} k\n * @return {number}\n */\nvar maximumHappinessSum = function(happiness, k) {\n    \n};",
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                    "code": "class Solution {\n\n    /**\n     * @param Integer[] $happiness\n     * @param Integer $k\n     * @return Integer\n     */\n    function maximumHappinessSum($happiness, $k) {\n        \n    }\n}",
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                    "code": "# @param {Integer[]} happiness\n# @param {Integer} k\n# @return {Integer}\ndef maximum_happiness_sum(happiness, k)\n    \nend",
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                    "code": "impl Solution {\n    pub fn maximum_happiness_sum(happiness: Vec<i32>, k: i32) -> i64 {\n        \n    }\n}",
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            "hints": [
                "Since all the unselected numbers are decreasing at the same rate, we should greedily select <code>k</code> largest values.",
                "The <code>i<sup>th</code> largest number (<code>i = 1, 2, 3,…k</code>) should decrease by <code>(i - 1)</code> when it is picked.",
                "Add <code>0</code> if the decreased value is negative."
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