mirror of
https://gitee.com/coder-xiaomo/leetcode-problemset
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183 lines
17 KiB
JSON
183 lines
17 KiB
JSON
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"content": "<p>In the video game Fallout 4, the quest <strong>"Road to Freedom"</strong> requires players to reach a metal dial called the <strong>"Freedom Trail Ring"</strong> and use the dial to spell a specific keyword to open the door.</p>\n\n<p>Given a string <code>ring</code> that represents the code engraved on the outer ring and another string <code>key</code> that represents the keyword that needs to be spelled, return <em>the minimum number of steps to spell all the characters in the keyword</em>.</p>\n\n<p>Initially, the first character of the ring is aligned at the <code>"12:00"</code> direction. You should spell all the characters in <code>key</code> one by one by rotating <code>ring</code> clockwise or anticlockwise to make each character of the string key aligned at the <code>"12:00"</code> direction and then by pressing the center button.</p>\n\n<p>At the stage of rotating the ring to spell the key character <code>key[i]</code>:</p>\n\n<ol>\n\t<li>You can rotate the ring clockwise or anticlockwise by one place, which counts as <strong>one step</strong>. The final purpose of the rotation is to align one of <code>ring</code>'s characters at the <code>"12:00"</code> direction, where this character must equal <code>key[i]</code>.</li>\n\t<li>If the character <code>key[i]</code> has been aligned at the <code>"12:00"</code> direction, press the center button to spell, which also counts as <strong>one step</strong>. After the pressing, you could begin to spell the next character in the key (next stage). Otherwise, you have finished all the spelling.</li>\n</ol>\n\n<p> </p>\n<p><strong class=\"example\">Example 1:</strong></p>\n<img src=\"https://assets.leetcode.com/uploads/2018/10/22/ring.jpg\" style=\"width: 450px; height: 450px;\" />\n<pre>\n<strong>Input:</strong> ring = "godding", key = "gd"\n<strong>Output:</strong> 4\n<strong>Explanation:</strong>\nFor the first key character 'g', since it is already in place, we just need 1 step to spell this character. \nFor the second key character 'd', we need to rotate the ring "godding" anticlockwise by two steps to make it become "ddinggo".\nAlso, we need 1 more step for spelling.\nSo the final output is 4.\n</pre>\n\n<p><strong class=\"example\">Example 2:</strong></p>\n\n<pre>\n<strong>Input:</strong> ring = "godding", key = "godding"\n<strong>Output:</strong> 13\n</pre>\n\n<p> </p>\n<p><strong>Constraints:</strong></p>\n\n<ul>\n\t<li><code>1 <= ring.length, key.length <= 100</code></li>\n\t<li><code>ring</code> and <code>key</code> consist of only lower case English letters.</li>\n\t<li>It is guaranteed that <code>key</code> could always be spelled by rotating <code>ring</code>.</li>\n</ul>\n",
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"code": "class Solution(object):\n def findRotateSteps(self, ring, key):\n \"\"\"\n :type ring: str\n :type key: str\n :rtype: int\n \"\"\"\n ",
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"code": "# @param {String} ring\n# @param {String} key\n# @return {Integer}\ndef find_rotate_steps(ring, key)\n \nend",
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"code": "impl Solution {\n pub fn find_rotate_steps(ring: String, key: String) -> i32 {\n \n }\n}",
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"code": "-spec find_rotate_steps(Ring :: unicode:unicode_binary(), Key :: unicode:unicode_binary()) -> integer().\nfind_rotate_steps(Ring, Key) ->\n .",
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