leetcode-problemset/leetcode/originData/find-the-minimum-cost-array-permutation.json

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            "title": "Find the Minimum Cost Array Permutation",
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            "content": "<p>You are given an array <code>nums</code> which is a <span data-keyword=\"permutation\">permutation</span> of <code>[0, 1, 2, ..., n - 1]</code>. The <strong>score</strong> of any permutation of <code>[0, 1, 2, ..., n - 1]</code> named <code>perm</code> is defined as:</p>\n\n<p><code>score(perm) = |perm[0] - nums[perm[1]]| + |perm[1] - nums[perm[2]]| + ... + |perm[n - 1] - nums[perm[0]]|</code></p>\n\n<p>Return the permutation <code>perm</code> which has the <strong>minimum</strong> possible score. If <em>multiple</em> permutations exist with this score, return the one that is <span data-keyword=\"lexicographically-smaller-array\">lexicographically smallest</span> among them.</p>\n\n<p>&nbsp;</p>\n<p><strong class=\"example\">Example 1:</strong></p>\n\n<div class=\"example-block\">\n<p><strong>Input:</strong> <span class=\"example-io\">nums = [1,0,2]</span></p>\n\n<p><strong>Output:</strong> <span class=\"example-io\">[0,1,2]</span></p>\n\n<p><strong>Explanation:</strong></p>\n\n<p><strong><img alt=\"\" src=\"https://assets.leetcode.com/uploads/2024/04/04/example0gif.gif\" style=\"width: 235px; height: 235px;\" /></strong></p>\n\n<p>The lexicographically smallest permutation with minimum cost is <code>[0,1,2]</code>. The cost of this permutation is <code>|0 - 0| + |1 - 2| + |2 - 1| = 2</code>.</p>\n</div>\n\n<p><strong class=\"example\">Example 2:</strong></p>\n\n<div class=\"example-block\">\n<p><strong>Input:</strong> <span class=\"example-io\">nums = [0,2,1]</span></p>\n\n<p><strong>Output:</strong> <span class=\"example-io\">[0,2,1]</span></p>\n\n<p><strong>Explanation:</strong></p>\n\n<p><strong><img alt=\"\" src=\"https://assets.leetcode.com/uploads/2024/04/04/example1gif.gif\" style=\"width: 235px; height: 235px;\" /></strong></p>\n\n<p>The lexicographically smallest permutation with minimum cost is <code>[0,2,1]</code>. The cost of this permutation is <code>|0 - 1| + |2 - 2| + |1 - 0| = 2</code>.</p>\n</div>\n\n<p>&nbsp;</p>\n<p><strong>Constraints:</strong></p>\n\n<ul>\n\t<li><code>2 &lt;= n == nums.length &lt;= 14</code></li>\n\t<li><code>nums</code> is a permutation of <code>[0, 1, 2, ..., n - 1]</code>.</li>\n</ul>\n",
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                    "code": "class Solution {\npublic:\n    vector<int> findPermutation(vector<int>& nums) {\n        \n    }\n};",
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                    "code": "class Solution(object):\n    def findPermutation(self, nums):\n        \"\"\"\n        :type nums: List[int]\n        :rtype: List[int]\n        \"\"\"\n        ",
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                    "code": "/**\n * Note: The returned array must be malloced, assume caller calls free().\n */\nint* findPermutation(int* nums, int numsSize, int* returnSize) {\n    \n}",
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                    "code": "defmodule Solution do\n  @spec find_permutation(nums :: [integer]) :: [integer]\n  def find_permutation(nums) do\n    \n  end\nend",
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            "hints": [
                "The score function is cyclic, so we can always set <code>perm[0] = 0</code> for the smallest lexical order.",
                "It’s similar to the Traveling Salesman Problem. Use Dynamic Programming.",
                "Use a bitmask to track which elements have been assigned to <code>perm</code>."
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