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leetcode-problemset/leetcode/originData/find-polygon-with-the-largest-perimeter.json
2023-12-29 14:49:55 +08:00

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{
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"title": "Find Polygon With the Largest Perimeter",
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"content": "<p>You are given an array of <strong>positive</strong> integers <code>nums</code> of length <code>n</code>.</p>\n\n<p>A <strong>polygon</strong> is a closed plane figure that has at least <code>3</code> sides. The <strong>longest side</strong> of a polygon is <strong>smaller</strong> than the sum of its other sides.</p>\n\n<p>Conversely, if you have <code>k</code> (<code>k &gt;= 3</code>) <strong>positive</strong> real numbers <code>a<sub>1</sub></code>, <code>a<sub>2</sub></code>, <code>a<sub>3</sub></code>, ..., <code>a<sub>k</sub></code> where <code>a<sub>1</sub> &lt;= a<sub>2</sub> &lt;= a<sub>3</sub> &lt;= ... &lt;= a<sub>k</sub></code> <strong>and</strong> <code>a<sub>1</sub> + a<sub>2</sub> + a<sub>3</sub> + ... + a<sub>k-1</sub> &gt; a<sub>k</sub></code>, then there <strong>always</strong> exists a polygon with <code>k</code> sides whose lengths are <code>a<sub>1</sub></code>, <code>a<sub>2</sub></code>, <code>a<sub>3</sub></code>, ..., <code>a<sub>k</sub></code>.</p>\n\n<p>The <strong>perimeter</strong> of a polygon is the sum of lengths of its sides.</p>\n\n<p>Return <em>the <strong>largest</strong> possible <strong>perimeter</strong> of a <strong>polygon</strong> whose sides can be formed from</em> <code>nums</code>, <em>or</em> <code>-1</code> <em>if it is not possible to create a polygon</em>.</p>\n\n<p>&nbsp;</p>\n<p><strong class=\"example\">Example 1:</strong></p>\n\n<pre>\n<strong>Input:</strong> nums = [5,5,5]\n<strong>Output:</strong> 15\n<strong>Explanation:</strong> The only possible polygon that can be made from nums has 3 sides: 5, 5, and 5. The perimeter is 5 + 5 + 5 = 15.\n</pre>\n\n<p><strong class=\"example\">Example 2:</strong></p>\n\n<pre>\n<strong>Input:</strong> nums = [1,12,1,2,5,50,3]\n<strong>Output:</strong> 12\n<strong>Explanation:</strong> The polygon with the largest perimeter which can be made from nums has 5 sides: 1, 1, 2, 3, and 5. The perimeter is 1 + 1 + 2 + 3 + 5 = 12.\nWe cannot have a polygon with either 12 or 50 as the longest side because it is not possible to include 2 or more smaller sides that have a greater sum than either of them.\nIt can be shown that the largest possible perimeter is 12.\n</pre>\n\n<p><strong class=\"example\">Example 3:</strong></p>\n\n<pre>\n<strong>Input:</strong> nums = [5,5,50]\n<strong>Output:</strong> -1\n<strong>Explanation:</strong> There is no possible way to form a polygon from nums, as a polygon has at least 3 sides and 50 &gt; 5 + 5.\n</pre>\n\n<p>&nbsp;</p>\n<p><strong>Constraints:</strong></p>\n\n<ul>\n\t<li><code>3 &lt;= n &lt;= 10<sup>5</sup></code></li>\n\t<li><code>1 &lt;= nums[i] &lt;= 10<sup>9</sup></code></li>\n</ul>\n",
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"hints": [
"Sort the array.",
"Use greedy algorithm. If we select an edge as the longest side, it is always better to pick up all the edges with length no longer than this longest edge.",
"Note that the number of edges should not be less than 3."
],
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