mirror of
https://gitee.com/coder-xiaomo/leetcode-problemset
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193 lines
20 KiB
JSON
193 lines
20 KiB
JSON
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"question": {
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"questionId": "3546",
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"questionFrontendId": "3261",
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"boundTopicId": null,
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"title": "Count Substrings That Satisfy K-Constraint II",
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"titleSlug": "count-substrings-that-satisfy-k-constraint-ii",
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"content": "<p>You are given a <strong>binary</strong> string <code>s</code> and an integer <code>k</code>.</p>\n\n<p>You are also given a 2D integer array <code>queries</code>, where <code>queries[i] = [l<sub>i</sub>, r<sub>i</sub>]</code>.</p>\n\n<p>A <strong>binary string</strong> satisfies the <strong>k-constraint</strong> if <strong>either</strong> of the following conditions holds:</p>\n\n<ul>\n\t<li>The number of <code>0</code>'s in the string is at most <code>k</code>.</li>\n\t<li>The number of <code>1</code>'s in the string is at most <code>k</code>.</li>\n</ul>\n\n<p>Return an integer array <code>answer</code>, where <code>answer[i]</code> is the number of <span data-keyword=\"substring-nonempty\">substrings</span> of <code>s[l<sub>i</sub>..r<sub>i</sub>]</code> that satisfy the <strong>k-constraint</strong>.</p>\n\n<p> </p>\n<p><strong class=\"example\">Example 1:</strong></p>\n\n<div class=\"example-block\">\n<p><strong>Input:</strong> <span class=\"example-io\">s = "0001111", k = 2, queries = [[0,6]]</span></p>\n\n<p><strong>Output:</strong> <span class=\"example-io\">[26]</span></p>\n\n<p><strong>Explanation:</strong></p>\n\n<p>For the query <code>[0, 6]</code>, all substrings of <code>s[0..6] = "0001111"</code> satisfy the k-constraint except for the substrings <code>s[0..5] = "000111"</code> and <code>s[0..6] = "0001111"</code>.</p>\n</div>\n\n<p><strong class=\"example\">Example 2:</strong></p>\n\n<div class=\"example-block\">\n<p><strong>Input:</strong> <span class=\"example-io\">s = "010101", k = 1, queries = [[0,5],[1,4],[2,3]]</span></p>\n\n<p><strong>Output:</strong> <span class=\"example-io\">[15,9,3]</span></p>\n\n<p><strong>Explanation:</strong></p>\n\n<p>The substrings of <code>s</code> with a length greater than 3 do not satisfy the k-constraint.</p>\n</div>\n\n<p> </p>\n<p><strong>Constraints:</strong></p>\n\n<ul>\n\t<li><code>1 <= s.length <= 10<sup>5</sup></code></li>\n\t<li><code>s[i]</code> is either <code>'0'</code> or <code>'1'</code>.</li>\n\t<li><code>1 <= k <= s.length</code></li>\n\t<li><code>1 <= queries.length <= 10<sup>5</sup></code></li>\n\t<li><code>queries[i] == [l<sub>i</sub>, r<sub>i</sub>]</code></li>\n\t<li><code>0 <= l<sub>i</sub> <= r<sub>i</sub> < s.length</code></li>\n\t<li>All queries are distinct.</li>\n</ul>\n",
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"difficulty": "Hard",
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"exampleTestcases": "\"0001111\"\n2\n[[0,6]]\n\"010101\"\n1\n[[0,5],[1,4],[2,3]]",
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"categoryTitle": "Algorithms",
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"code": "class Solution {\npublic:\n vector<long long> countKConstraintSubstrings(string s, int k, vector<vector<int>>& queries) {\n \n }\n};",
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"code": "class Solution {\n public long[] countKConstraintSubstrings(String s, int k, int[][] queries) {\n \n }\n}",
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"code": "class Solution(object):\n def countKConstraintSubstrings(self, s, k, queries):\n \"\"\"\n :type s: str\n :type k: int\n :type queries: List[List[int]]\n :rtype: List[int]\n \"\"\"\n ",
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"code": "/**\n * Note: The returned array must be malloced, assume caller calls free().\n */\nlong long* countKConstraintSubstrings(char* s, int k, int** queries, int queriesSize, int* queriesColSize, int* returnSize) {\n \n}",
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"code": "class Solution {\n\n /**\n * @param String $s\n * @param Integer $k\n * @param Integer[][] $queries\n * @return Integer[]\n */\n function countKConstraintSubstrings($s, $k, $queries) {\n \n }\n}",
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"code": "class Solution {\n fun countKConstraintSubstrings(s: String, k: Int, queries: Array<IntArray>): LongArray {\n \n }\n}",
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"code": "class Solution {\n List<int> countKConstraintSubstrings(String s, int k, List<List<int>> queries) {\n \n }\n}",
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"code": "func countKConstraintSubstrings(s string, k int, queries [][]int) []int64 {\n \n}",
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"code": "# @param {String} s\n# @param {Integer} k\n# @param {Integer[][]} queries\n# @return {Integer[]}\ndef count_k_constraint_substrings(s, k, queries)\n \nend",
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"code": "object Solution {\n def countKConstraintSubstrings(s: String, k: Int, queries: Array[Array[Int]]): Array[Long] = {\n \n }\n}",
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"code": "impl Solution {\n pub fn count_k_constraint_substrings(s: String, k: i32, queries: Vec<Vec<i32>>) -> Vec<i64> {\n \n }\n}",
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"code": "(define/contract (count-k-constraint-substrings s k queries)\n (-> string? exact-integer? (listof (listof exact-integer?)) (listof exact-integer?))\n )",
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"code": "-spec count_k_constraint_substrings(S :: unicode:unicode_binary(), K :: integer(), Queries :: [[integer()]]) -> [integer()].\ncount_k_constraint_substrings(S, K, Queries) ->\n .",
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"code": "defmodule Solution do\n @spec count_k_constraint_substrings(s :: String.t, k :: integer, queries :: [[integer]]) :: [integer]\n def count_k_constraint_substrings(s, k, queries) do\n \n end\nend",
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"Answering online queries is tough. Try to answer them offline since the queries are known beforehand.",
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"For each index, how do you calculate the left boundary so that the given condition is satisfied?",
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"Using the precomputed left boundaries and a range data structure, you can now answer the queries optimally."
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],
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"sampleTestCase": "\"0001111\"\n2\n[[0,6]]",
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