mirror of
https://gitee.com/coder-xiaomo/leetcode-problemset
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176 lines
17 KiB
JSON
176 lines
17 KiB
JSON
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"title": "Count Stepping Numbers in Range",
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"content": "<p>Given two positive integers <code>low</code> and <code>high</code> represented as strings, find the count of <strong>stepping numbers</strong> in the inclusive range <code>[low, high]</code>.</p>\n\n<p>A <strong>stepping number</strong> is an integer such that all of its adjacent digits have an absolute difference of <strong>exactly</strong> <code>1</code>.</p>\n\n<p>Return <em>an integer denoting the count of stepping numbers in the inclusive range</em> <code>[low, high]</code><em>. </em></p>\n\n<p>Since the answer may be very large, return it <strong>modulo</strong> <code>10<sup>9</sup> + 7</code>.</p>\n\n<p><strong>Note:</strong> A stepping number should not have a leading zero.</p>\n\n<p> </p>\n<p><strong class=\"example\">Example 1:</strong></p>\n\n<pre>\n<strong>Input:</strong> low = "1", high = "11"\n<strong>Output:</strong> 10\n<strong>Explanation: </strong>The stepping numbers in the range [1,11] are 1, 2, 3, 4, 5, 6, 7, 8, 9 and 10. There are a total of 10 stepping numbers in the range. Hence, the output is 10.</pre>\n\n<p><strong class=\"example\">Example 2:</strong></p>\n\n<pre>\n<strong>Input:</strong> low = "90", high = "101"\n<strong>Output:</strong> 2\n<strong>Explanation: </strong>The stepping numbers in the range [90,101] are 98 and 101. There are a total of 2 stepping numbers in the range. Hence, the output is 2. </pre>\n\n<p> </p>\n<p><strong>Constraints:</strong></p>\n\n<ul>\n\t<li><code>1 <= int(low) <= int(high) < 10<sup>100</sup></code></li>\n\t<li><code>1 <= low.length, high.length <= 100</code></li>\n\t<li><code>low</code> and <code>high</code> consist of only digits.</li>\n\t<li><code>low</code> and <code>high</code> don't have any leading zeros.</li>\n</ul>\n",
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"code": "# @param {String} low\n# @param {String} high\n# @return {Integer}\ndef count_stepping_numbers(low, high)\n \nend",
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"code": "impl Solution {\n pub fn count_stepping_numbers(low: String, high: String) -> i32 {\n \n }\n}",
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"code": "-spec count_stepping_numbers(Low :: unicode:unicode_binary(), High :: unicode:unicode_binary()) -> integer().\ncount_stepping_numbers(Low, High) ->\n .",
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"code": "defmodule Solution do\n @spec count_stepping_numbers(low :: String.t, high :: String.t) :: integer\n def count_stepping_numbers(low, high) do\n\n end\nend",
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"hints": [
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"Calculate the number of stepping numbers in the range [1, high] and subtract the number of stepping numbers in the range [1, low - 1].",
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"The main problem is calculating the number of stepping numbers in the range [1, x].",
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"First, calculate the number of stepping numbers shorter than x in length, which can be done using dynamic programming. (dp[i][j] is the number of i-digit stepping numbers ending with digit j).",
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"Finally, calculate the number of stepping numbers that have the same length as x similarly. However, this time we need to maintain whether the prefix (in string) is smaller than or equal to x in the DP state."
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],
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"sampleTestCase": "\"1\"\n\"11\"",
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