mirror of
https://gitee.com/coder-xiaomo/leetcode-problemset
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199 lines
18 KiB
JSON
199 lines
18 KiB
JSON
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"title": "Contains Duplicate III",
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"content": "<p>You are given an integer array <code>nums</code> and two integers <code>indexDiff</code> and <code>valueDiff</code>.</p>\n\n<p>Find a pair of indices <code>(i, j)</code> such that:</p>\n\n<ul>\n\t<li><code>i != j</code>,</li>\n\t<li><code>abs(i - j) <= indexDiff</code>.</li>\n\t<li><code>abs(nums[i] - nums[j]) <= valueDiff</code>, and</li>\n</ul>\n\n<p>Return <code>true</code><em> if such pair exists or </em><code>false</code><em> otherwise</em>.</p>\n\n<p> </p>\n<p><strong class=\"example\">Example 1:</strong></p>\n\n<pre>\n<strong>Input:</strong> nums = [1,2,3,1], indexDiff = 3, valueDiff = 0\n<strong>Output:</strong> true\n<strong>Explanation:</strong> We can choose (i, j) = (0, 3).\nWe satisfy the three conditions:\ni != j --> 0 != 3\nabs(i - j) <= indexDiff --> abs(0 - 3) <= 3\nabs(nums[i] - nums[j]) <= valueDiff --> abs(1 - 1) <= 0\n</pre>\n\n<p><strong class=\"example\">Example 2:</strong></p>\n\n<pre>\n<strong>Input:</strong> nums = [1,5,9,1,5,9], indexDiff = 2, valueDiff = 3\n<strong>Output:</strong> false\n<strong>Explanation:</strong> After trying all the possible pairs (i, j), we cannot satisfy the three conditions, so we return false.\n</pre>\n\n<p> </p>\n<p><strong>Constraints:</strong></p>\n\n<ul>\n\t<li><code>2 <= nums.length <= 10<sup>5</sup></code></li>\n\t<li><code>-10<sup>9</sup> <= nums[i] <= 10<sup>9</sup></code></li>\n\t<li><code>1 <= indexDiff <= nums.length</code></li>\n\t<li><code>0 <= valueDiff <= 10<sup>9</sup></code></li>\n</ul>\n",
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"code": "# @param {Integer[]} nums\n# @param {Integer} index_diff\n# @param {Integer} value_diff\n# @return {Boolean}\ndef contains_nearby_almost_duplicate(nums, index_diff, value_diff)\n \nend",
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"code": "impl Solution {\n pub fn contains_nearby_almost_duplicate(nums: Vec<i32>, index_diff: i32, value_diff: i32) -> bool {\n \n }\n}",
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"Time complexity O(n logk) - This will give an indication that sorting is involved for k elements.",
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"Use already existing state to evaluate next state - Like, a set of k sorted numbers are only needed to be tracked. When we are processing the next number in array, then we can utilize the existing sorted state and it is not necessary to sort next overlapping set of k numbers again."
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