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leetcode-problemset/leetcode-cn/problem (English)/距离最小相等元素查询(English) [closest-equal-element-queries].html
2025-04-03 23:09:51 +08:00

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<p>You are given a <strong>circular</strong> array <code>nums</code> and an array <code>queries</code>.</p>
<p>For each query <code>i</code>, you have to find the following:</p>
<ul>
<li>The <strong>minimum</strong> distance between the element at index <code>queries[i]</code> and <strong>any</strong> other index <code>j</code> in the <strong>circular</strong> array, where <code>nums[j] == nums[queries[i]]</code>. If no such index exists, the answer for that query should be -1.</li>
</ul>
<p>Return an array <code>answer</code> of the <strong>same</strong> size as <code>queries</code>, where <code>answer[i]</code> represents the result for query <code>i</code>.</p>
<p>&nbsp;</p>
<p><strong class="example">Example 1:</strong></p>
<div class="example-block">
<p><strong>Input:</strong> <span class="example-io">nums = [1,3,1,4,1,3,2], queries = [0,3,5]</span></p>
<p><strong>Output:</strong> <span class="example-io">[2,-1,3]</span></p>
<p><strong>Explanation:</strong></p>
<ul>
<li>Query 0: The element at <code>queries[0] = 0</code> is <code>nums[0] = 1</code>. The nearest index with the same value is 2, and the distance between them is 2.</li>
<li>Query 1: The element at <code>queries[1] = 3</code> is <code>nums[3] = 4</code>. No other index contains 4, so the result is -1.</li>
<li>Query 2: The element at <code>queries[2] = 5</code> is <code>nums[5] = 3</code>. The nearest index with the same value is 1, and the distance between them is 3 (following the circular path: <code>5 -&gt; 6 -&gt; 0 -&gt; 1</code>).</li>
</ul>
</div>
<p><strong class="example">Example 2:</strong></p>
<div class="example-block">
<p><strong>Input:</strong> <span class="example-io">nums = [1,2,3,4], queries = [0,1,2,3]</span></p>
<p><strong>Output:</strong> <span class="example-io">[-1,-1,-1,-1]</span></p>
<p><strong>Explanation:</strong></p>
<p>Each value in <code>nums</code> is unique, so no index shares the same value as the queried element. This results in -1 for all queries.</p>
</div>
<p>&nbsp;</p>
<p><strong>Constraints:</strong></p>
<ul>
<li><code>1 &lt;= queries.length &lt;= nums.length &lt;= 10<sup>5</sup></code></li>
<li><code>1 &lt;= nums[i] &lt;= 10<sup>6</sup></code></li>
<li><code>0 &lt;= queries[i] &lt; nums.length</code></li>
</ul>