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leetcode-problemset/leetcode-cn/problem (English)/计数器(English) [counter].html

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<p>Given an integer&nbsp;<code>n</code>,&nbsp;return a <code>counter</code> function. This <code>counter</code> function initially returns&nbsp;<code>n</code>&nbsp;and then returns 1 more than the previous value every subsequent time it is called (<code>n</code>, <code>n + 1</code>, <code>n + 2</code>, etc).</p>
<p>&nbsp;</p>
<p><strong class="example">Example 1:</strong></p>
<pre>
<strong>Input:</strong>
n = 10
[&quot;call&quot;,&quot;call&quot;,&quot;call&quot;]
<strong>Output:</strong> [10,11,12]
<strong>Explanation:
</strong>counter() = 10 // The first time counter() is called, it returns n.
counter() = 11 // Returns 1 more than the previous time.
counter() = 12 // Returns 1 more than the previous time.
</pre>
<p><strong class="example">Example 2:</strong></p>
<pre>
<strong>Input:</strong>
n = -2
[&quot;call&quot;,&quot;call&quot;,&quot;call&quot;,&quot;call&quot;,&quot;call&quot;]
<strong>Output:</strong> [-2,-1,0,1,2]
<strong>Explanation:</strong> counter() initially returns -2. Then increases after each sebsequent call.
</pre>
<p>&nbsp;</p>
<p><strong>Constraints:</strong></p>
<ul>
<li><code>-1000<sup>&nbsp;</sup>&lt;= n &lt;= 1000</code></li>
<li><code>0 &lt;= calls.length &lt;= 1000</code></li>
<li><code>calls[i] === &quot;call&quot;</code></li>
</ul>