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leetcode-problemset/leetcode-cn/problem (English)/统计特殊三元组(English) [count-special-triplets].html
2025-06-18 01:10:28 +08:00

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<p>You are given an integer array <code>nums</code>.</p>
<p>A <strong>special triplet</strong> is defined as a triplet of indices <code>(i, j, k)</code> such that:</p>
<ul>
<li><code>0 &lt;= i &lt; j &lt; k &lt; n</code>, where <code>n = nums.length</code></li>
<li><code>nums[i] == nums[j] * 2</code></li>
<li><code>nums[k] == nums[j] * 2</code></li>
</ul>
<p>Return the total number of <strong>special triplets</strong> in the array.</p>
<p>Since the answer may be large, return it <strong>modulo</strong> <code>10<sup>9</sup> + 7</code>.</p>
<p>&nbsp;</p>
<p><strong class="example">Example 1:</strong></p>
<div class="example-block">
<p><strong>Input:</strong> <span class="example-io">nums = [6,3,6]</span></p>
<p><strong>Output:</strong> <span class="example-io">1</span></p>
<p><strong>Explanation:</strong></p>
<p>The only special triplet is <code>(i, j, k) = (0, 1, 2)</code>, where:</p>
<ul>
<li><code>nums[0] = 6</code>, <code>nums[1] = 3</code>, <code>nums[2] = 6</code></li>
<li><code>nums[0] = nums[1] * 2 = 3 * 2 = 6</code></li>
<li><code>nums[2] = nums[1] * 2 = 3 * 2 = 6</code></li>
</ul>
</div>
<p><strong class="example">Example 2:</strong></p>
<div class="example-block">
<p><strong>Input:</strong> <span class="example-io">nums = [0,1,0,0]</span></p>
<p><strong>Output:</strong> <span class="example-io">1</span></p>
<p><strong>Explanation:</strong></p>
<p>The only special triplet is <code>(i, j, k) = (0, 2, 3)</code>, where:</p>
<ul>
<li><code>nums[0] = 0</code>, <code>nums[2] = 0</code>, <code>nums[3] = 0</code></li>
<li><code>nums[0] = nums[2] * 2 = 0 * 2 = 0</code></li>
<li><code>nums[3] = nums[2] * 2 = 0 * 2 = 0</code></li>
</ul>
</div>
<p><strong class="example">Example 3:</strong></p>
<div class="example-block">
<p><strong>Input:</strong> <span class="example-io">nums = [8,4,2,8,4]</span></p>
<p><strong>Output:</strong> <span class="example-io">2</span></p>
<p><strong>Explanation:</strong></p>
<p>There are exactly two special triplets:</p>
<ul>
<li><code>(i, j, k) = (0, 1, 3)</code>
<ul>
<li><code>nums[0] = 8</code>, <code>nums[1] = 4</code>, <code>nums[3] = 8</code></li>
<li><code>nums[0] = nums[1] * 2 = 4 * 2 = 8</code></li>
<li><code>nums[3] = nums[1] * 2 = 4 * 2 = 8</code></li>
</ul>
</li>
<li><code>(i, j, k) = (1, 2, 4)</code>
<ul>
<li><code>nums[1] = 4</code>, <code>nums[2] = 2</code>, <code>nums[4] = 4</code></li>
<li><code>nums[1] = nums[2] * 2 = 2 * 2 = 4</code></li>
<li><code>nums[4] = nums[2] * 2 = 2 * 2 = 4</code></li>
</ul>
</li>
</ul>
</div>
<p>&nbsp;</p>
<p><strong>Constraints:</strong></p>
<ul>
<li><code>3 &lt;= n == nums.length &lt;= 10<sup>5</sup></code></li>
<li><code>0 &lt;= nums[i] &lt;= 10<sup>5</sup></code></li>
</ul>