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leetcode-problemset/leetcode-cn/problem (English)/游戏玩法分析 IV(English) [game-play-analysis-iv].html
2025-09-29 14:43:44 +08:00

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<p>Table: <code>Activity</code></p>
<pre>
+--------------+---------+
| Column Name | Type |
+--------------+---------+
| player_id | int |
| device_id | int |
| event_date | date |
| games_played | int |
+--------------+---------+
(player_id, event_date) is the primary key (combination of columns with unique values) of this table.
This table shows the activity of players of some games.
Each row is a record of a player who logged in and played a number of games (possibly 0) before logging out on someday using some device.
</pre>
<p> </p>
<p>Write a solution to report the <strong>fraction</strong> of players that logged in again on the day after the day they first logged in, <strong>rounded to 2 decimal places</strong>. In other words, you need to determine the number of players who logged in on the day immediately following their initial login, and divide it by the number of total players.</p>
<p>The result format is in the following example.</p>
<p>&nbsp;</p>
<p><strong class="example">Example 1:</strong></p>
<pre>
<strong>Input:</strong>
Activity table:
+-----------+-----------+------------+--------------+
| player_id | device_id | event_date | games_played |
+-----------+-----------+------------+--------------+
| 1 | 2 | 2016-03-01 | 5 |
| 1 | 2 | 2016-03-02 | 6 |
| 2 | 3 | 2017-06-25 | 1 |
| 3 | 1 | 2016-03-02 | 0 |
| 3 | 4 | 2018-07-03 | 5 |
+-----------+-----------+------------+--------------+
<strong>Output:</strong>
+-----------+
| fraction |
+-----------+
| 0.33 |
+-----------+
<strong>Explanation:</strong>
Only the player with id 1 logged back in after the first day he had logged in so the answer is 1/3 = 0.33
</pre>