mirror of
https://gitee.com/coder-xiaomo/leetcode-problemset
synced 2025-01-10 18:48:13 +08:00
46 lines
2.7 KiB
HTML
46 lines
2.7 KiB
HTML
<p>You are given a <strong>0-indexed</strong> integer array <code>nums</code> and an integer <code>pivot</code>. Rearrange <code>nums</code> such that the following conditions are satisfied:</p>
|
|
|
|
<ul>
|
|
<li>Every element less than <code>pivot</code> appears <strong>before</strong> every element greater than <code>pivot</code>.</li>
|
|
<li>Every element equal to <code>pivot</code> appears <strong>in between</strong> the elements less than and greater than <code>pivot</code>.</li>
|
|
<li>The <strong>relative order</strong> of the elements less than <code>pivot</code> and the elements greater than <code>pivot</code> is maintained.
|
|
<ul>
|
|
<li>More formally, consider every <code>p<sub>i</sub></code>, <code>p<sub>j</sub></code> where <code>p<sub>i</sub></code> is the new position of the <code>i<sup>th</sup></code> element and <code>p<sub>j</sub></code> is the new position of the <code>j<sup>th</sup></code> element. For elements less than <code>pivot</code>, if <code>i < j</code> and <code>nums[i] < pivot</code> and <code>nums[j] < pivot</code>, then <code>p<sub>i</sub> < p<sub>j</sub></code>. Similarly for elements greater than <code>pivot</code>, if <code>i < j</code> and <code>nums[i] > pivot</code> and <code>nums[j] > pivot</code>, then <code>p<sub>i</sub> < p<sub>j</sub></code>.</li>
|
|
</ul>
|
|
</li>
|
|
</ul>
|
|
|
|
<p>Return <code>nums</code><em> after the rearrangement.</em></p>
|
|
|
|
<p> </p>
|
|
<p><strong class="example">Example 1:</strong></p>
|
|
|
|
<pre>
|
|
<strong>Input:</strong> nums = [9,12,5,10,14,3,10], pivot = 10
|
|
<strong>Output:</strong> [9,5,3,10,10,12,14]
|
|
<strong>Explanation:</strong>
|
|
The elements 9, 5, and 3 are less than the pivot so they are on the left side of the array.
|
|
The elements 12 and 14 are greater than the pivot so they are on the right side of the array.
|
|
The relative ordering of the elements less than and greater than pivot is also maintained. [9, 5, 3] and [12, 14] are the respective orderings.
|
|
</pre>
|
|
|
|
<p><strong class="example">Example 2:</strong></p>
|
|
|
|
<pre>
|
|
<strong>Input:</strong> nums = [-3,4,3,2], pivot = 2
|
|
<strong>Output:</strong> [-3,2,4,3]
|
|
<strong>Explanation:</strong>
|
|
The element -3 is less than the pivot so it is on the left side of the array.
|
|
The elements 4 and 3 are greater than the pivot so they are on the right side of the array.
|
|
The relative ordering of the elements less than and greater than pivot is also maintained. [-3] and [4, 3] are the respective orderings.
|
|
</pre>
|
|
|
|
<p> </p>
|
|
<p><strong>Constraints:</strong></p>
|
|
|
|
<ul>
|
|
<li><code>1 <= nums.length <= 10<sup>5</sup></code></li>
|
|
<li><code>-10<sup>6</sup> <= nums[i] <= 10<sup>6</sup></code></li>
|
|
<li><code>pivot</code> equals to an element of <code>nums</code>.</li>
|
|
</ul>
|