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leetcode-problemset/leetcode-cn/problem (Chinese)/奇偶频次间的最大差值 I [maximum-difference-between-even-and-odd-frequency-i].html
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<p>给你一个由小写英文字母组成的字符串&nbsp;<code>s</code> 。请你找出字符串中两个字符的出现频次之间的 <strong>最大</strong> 差值,这两个字符需要满足:</p>
<ul>
<li>一个字符在字符串中出现 <strong>偶数次</strong></li>
<li>另一个字符在字符串中出现 <strong>奇数次</strong>&nbsp;</li>
</ul>
<p>返回 <strong>最大</strong> 差值,计算方法是出现 <strong>奇数次</strong> 字符的次数 <strong>减去</strong> 出现 <strong>偶数次</strong> 字符的次数。</p>
<p>&nbsp;</p>
<p><b>示例 1</b></p>
<div class="example-block">
<p><span class="example-io"><b>输入:</b>s = "aaaaabbc"</span></p>
<p><b>输出:</b>3</p>
<p><b>解释:</b></p>
<ul>
<li>字符&nbsp;<code>'a'</code>&nbsp;出现 <strong>奇数次</strong>&nbsp;,次数为&nbsp;<code><font face="monospace">5</font></code><font face="monospace"> ;字符</font>&nbsp;<code>'b'</code>&nbsp;出现 <strong>偶数次</strong> ,次数为&nbsp;<code><font face="monospace">2</font></code>&nbsp;</li>
<li>最大差值为&nbsp;<code>5 - 2 = 3</code>&nbsp;</li>
</ul>
</div>
<p><b>示例 2</b></p>
<div class="example-block">
<p><span class="example-io"><b>输入:</b>s = "abcabcab"</span></p>
<p><b>输出:</b>1</p>
<p><b>解释:</b></p>
<ul>
<li>字符&nbsp;<code>'a'</code>&nbsp;出现 <strong>奇数次</strong>&nbsp;,次数为&nbsp;<code><font face="monospace">3</font></code><font face="monospace"> ;字符</font>&nbsp;<code>'c'</code>&nbsp;出现 <strong>偶数次</strong>&nbsp;,次数为&nbsp;<font face="monospace">2 。</font></li>
<li>最大差值为&nbsp;<code>3 - 2 = 1</code></li>
</ul>
</div>
<p>&nbsp;</p>
<p><b>提示:</b></p>
<ul>
<li><code>3 &lt;= s.length &lt;= 100</code></li>
<li><code>s</code>&nbsp;仅由小写英文字母组成。</li>
<li><code>s</code>&nbsp;至少由一个出现奇数次的字符和一个出现偶数次的字符组成。</li>
</ul>