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leetcode-problemset/leetcode-cn/problem (Chinese)/两个数字的最大乘积 [maximum-product-of-two-digits].html
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<p>给定一个正整数 <code>n</code></p>
<p>返回 <strong>任意两位数字&nbsp;</strong>相乘所得的&nbsp;<strong>最大&nbsp;</strong>乘积。</p>
<p><strong>注意:</strong>如果某个数字在 <code>n</code> 中出现多次,你可以多次使用该数字。</p>
<p>&nbsp;</p>
<p><strong class="example">示例 1</strong></p>
<div class="example-block">
<p><strong>输入:</strong> <span class="example-io">n = 31</span></p>
<p><strong>输出:</strong> <span class="example-io">3</span></p>
<p><strong>解释:</strong></p>
<ul>
<li><code>n</code> 的数字是 <code>[3, 1]</code></li>
<li>任意两位数字相乘的结果为:<code>3 * 1 = 3</code></li>
<li>最大乘积为 3。</li>
</ul>
</div>
<p><strong class="example">示例 2</strong></p>
<div class="example-block">
<p><strong>输入:</strong> <span class="example-io">n = 22</span></p>
<p><strong>输出:</strong> <span class="example-io">4</span></p>
<p><strong>解释:</strong></p>
<ul>
<li><code>n</code> 的数字是 <code>[2, 2]</code></li>
<li>任意两位数字相乘的结果为:<code>2 * 2 = 4</code></li>
<li>最大乘积为 4。</li>
</ul>
</div>
<p><strong class="example">示例 3</strong></p>
<div class="example-block">
<p><strong>输入:</strong> <span class="example-io">n = 124</span></p>
<p><strong>输出:</strong> <span class="example-io">8</span></p>
<p><strong>解释:</strong></p>
<ul>
<li><code>n</code> 的数字是 <code>[1, 2, 4]</code></li>
<li>任意两位数字相乘的结果为:<code>1 * 2 = 2</code>, <code>1 * 4 = 4</code>, <code>2 * 4 = 8</code></li>
<li>最大乘积为 8。</li>
</ul>
</div>
<p>&nbsp;</p>
<p><strong>提示:</strong></p>
<ul>
<li><code>10 &lt;= n &lt;= 10<sup>9</sup></code></li>
</ul>