leetcode-problemset/leetcode-cn/originData/maximize-active-section-with-trade-i.json

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        "question": {
            "questionId": "3805",
            "questionFrontendId": "3499",
            "categoryTitle": "Algorithms",
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            "title": "Maximize Active Section with Trade I",
            "titleSlug": "maximize-active-section-with-trade-i",
            "content": "<p>You are given a binary string <code>s</code> of length <code>n</code>, where:</p>\n\n<ul>\n\t<li><code>&#39;1&#39;</code> represents an <strong>active</strong> section.</li>\n\t<li><code>&#39;0&#39;</code> represents an <strong>inactive</strong> section.</li>\n</ul>\n\n<p>You can perform <strong>at most one trade</strong> to maximize the number of active sections in <code>s</code>. In a trade, you:</p>\n\n<ul>\n\t<li>Convert a contiguous block of <code>&#39;1&#39;</code>s that is surrounded by <code>&#39;0&#39;</code>s to all <code>&#39;0&#39;</code>s.</li>\n\t<li>Afterward, convert a contiguous block of <code>&#39;0&#39;</code>s that is surrounded by <code>&#39;1&#39;</code>s to all <code>&#39;1&#39;</code>s.</li>\n</ul>\n\n<p>Return the <strong>maximum</strong> number of active sections in <code>s</code> after making the optimal trade.</p>\n\n<p><strong>Note:</strong> Treat <code>s</code> as if it is <strong>augmented</strong> with a <code>&#39;1&#39;</code> at both ends, forming <code>t = &#39;1&#39; + s + &#39;1&#39;</code>. The augmented <code>&#39;1&#39;</code>s <strong>do not</strong> contribute to the final count.</p>\n\n<p>&nbsp;</p>\n<p><strong class=\"example\">Example 1:</strong></p>\n\n<div class=\"example-block\">\n<p><strong>Input:</strong> <span class=\"example-io\">s = &quot;01&quot;</span></p>\n\n<p><strong>Output:</strong> <span class=\"example-io\">1</span></p>\n\n<p><strong>Explanation:</strong></p>\n\n<p>Because there is no block of <code>&#39;1&#39;</code>s surrounded by <code>&#39;0&#39;</code>s, no valid trade is possible. The maximum number of active sections is 1.</p>\n</div>\n\n<p><strong class=\"example\">Example 2:</strong></p>\n\n<div class=\"example-block\">\n<p><strong>Input:</strong> <span class=\"example-io\">s = &quot;0100&quot;</span></p>\n\n<p><strong>Output:</strong> <span class=\"example-io\">4</span></p>\n\n<p><strong>Explanation:</strong></p>\n\n<ul>\n\t<li>String <code>&quot;0100&quot;</code> &rarr; Augmented to <code>&quot;101001&quot;</code>.</li>\n\t<li>Choose <code>&quot;0100&quot;</code>, convert <code>&quot;10<u><strong>1</strong></u>001&quot;</code> &rarr; <code>&quot;1<u><strong>0000</strong></u>1&quot;</code> &rarr; <code>&quot;1<u><strong>1111</strong></u>1&quot;</code>.</li>\n\t<li>The final string without augmentation is <code>&quot;1111&quot;</code>. The maximum number of active sections is 4.</li>\n</ul>\n</div>\n\n<p><strong class=\"example\">Example 3:</strong></p>\n\n<div class=\"example-block\">\n<p><strong>Input:</strong> <span class=\"example-io\">s = &quot;1000100&quot;</span></p>\n\n<p><strong>Output:</strong> <span class=\"example-io\">7</span></p>\n\n<p><strong>Explanation:</strong></p>\n\n<ul>\n\t<li>String <code>&quot;1000100&quot;</code> &rarr; Augmented to <code>&quot;110001001&quot;</code>.</li>\n\t<li>Choose <code>&quot;000100&quot;</code>, convert <code>&quot;11000<u><strong>1</strong></u>001&quot;</code> &rarr; <code>&quot;11<u><strong>000000</strong></u>1&quot;</code> &rarr; <code>&quot;11<u><strong>111111</strong></u>1&quot;</code>.</li>\n\t<li>The final string without augmentation is <code>&quot;1111111&quot;</code>. The maximum number of active sections is 7.</li>\n</ul>\n</div>\n\n<p><strong class=\"example\">Example 4:</strong></p>\n\n<div class=\"example-block\">\n<p><strong>Input:</strong> <span class=\"example-io\">s = &quot;01010&quot;</span></p>\n\n<p><strong>Output:</strong> <span class=\"example-io\">4</span></p>\n\n<p><strong>Explanation:</strong></p>\n\n<ul>\n\t<li>String <code>&quot;01010&quot;</code> &rarr; Augmented to <code>&quot;1010101&quot;</code>.</li>\n\t<li>Choose <code>&quot;010&quot;</code>, convert <code>&quot;10<u><strong>1</strong></u>0101&quot;</code> &rarr; <code>&quot;1<u><strong>000</strong></u>101&quot;</code> &rarr; <code>&quot;1<u><strong>111</strong></u>101&quot;</code>.</li>\n\t<li>The final string without augmentation is <code>&quot;11110&quot;</code>. The maximum number of active sections is 4.</li>\n</ul>\n</div>\n\n<p>&nbsp;</p>\n<p><strong>Constraints:</strong></p>\n\n<ul>\n\t<li><code>1 &lt;= n == s.length &lt;= 10<sup>5</sup></code></li>\n\t<li><code>s[i]</code> is either <code>&#39;0&#39;</code> or <code>&#39;1&#39;</code></li>\n</ul>\n",
            "translatedTitle": "操作后最大活跃区段数 I",
            "translatedContent": "<p>给你一个长度为 <code>n</code> 的二进制字符串 <code>s</code>，其中：</p>\n\n<ul>\n\t<li><code>'1'</code> 表示一个 <strong>活跃</strong> 区段。</li>\n\t<li><code>'0'</code> 表示一个 <strong>非活跃</strong> 区段。</li>\n</ul>\n\n<p>你可以执行 <strong>最多一次操作</strong>&nbsp;来最大化 <code>s</code> 中的活跃区段数量。在一次操作中，你可以：</p>\n\n<ul>\n\t<li>将一个被 <code>'0'</code> 包围的连续 <code>'1'</code> 区块转换为全 <code>'0'</code>。</li>\n\t<li>然后，将一个被 <code>'1'</code> 包围的连续 <code>'0'</code> 区块转换为全 <code>'1'</code>。</li>\n</ul>\n\n<p>返回在执行最优操作后，<code>s</code> 中的 <strong>最大</strong> 活跃区段数。</p>\n\n<p><strong>注意：</strong>处理时需要在 <code>s</code> 的两侧加上 <code>'1'</code> ，即 <code>t = '1' + s + '1'</code>。这些加上的 <code>'1'</code> 不会影响最终的计数。</p>\n\n<p>&nbsp;</p>\n\n<p><strong class=\"example\">示例 1：</strong></p>\n\n<div class=\"example-block\">\n<p><strong>输入：</strong> <span class=\"example-io\">s = \"01\"</span></p>\n\n<p><strong>输出：</strong> <span class=\"example-io\">1</span></p>\n\n<p><strong>解释：</strong></p>\n\n<p>因为没有被 <code>'0'</code> 包围的 <code>'1'</code> 区块，因此无法进行有效操作。最大活跃区段数为 1。</p>\n</div>\n\n<p><strong class=\"example\">示例 2：</strong></p>\n\n<div class=\"example-block\">\n<p><strong>输入：</strong> <span class=\"example-io\">s = \"0100\"</span></p>\n\n<p><strong>输出：</strong> <span class=\"example-io\">4</span></p>\n\n<p><strong>解释：</strong></p>\n\n<ul>\n\t<li>字符串 <code>\"0100\"</code> → 两端加上 <code>'1'</code>&nbsp;后得到&nbsp;<code>\"101001\"</code>&nbsp;。</li>\n\t<li>选择 <code>\"0100\"</code>，<code>\"10<u><strong>1</strong></u>001\"</code> → <code>\"1<u><strong>0000</strong></u>1\"</code> → <code>\"1<u><strong>1111</strong></u>1\"</code>&nbsp;。</li>\n\t<li>最终的字符串去掉两端的 <code>'1'</code>&nbsp;后为 <code>\"1111\"</code>&nbsp;。最大活跃区段数为 4。</li>\n</ul>\n</div>\n\n<p><strong class=\"example\">示例 3：</strong></p>\n\n<div class=\"example-block\">\n<p><strong>输入：</strong> <span class=\"example-io\">s = \"1000100\"</span></p>\n\n<p><strong>输出：</strong> <span class=\"example-io\">7</span></p>\n\n<p><strong>解释：</strong></p>\n\n<ul>\n\t<li>字符串 <code>\"1000100\"</code> → 两端加上 <code>'1'</code>&nbsp;后得到 <code>\"110001001\"</code>&nbsp;。</li>\n\t<li>选择 <code>\"000100\"</code>，<code>\"11000<u><strong>1</strong></u>001\"</code> → <code>\"11<u><strong>000000</strong></u>1\"</code> → <code>\"11<u><strong>111111</strong></u>1\"</code>。</li>\n\t<li>最终的字符串去掉两端的 <code>'1'</code>&nbsp;后为 <code>\"1111111\"</code>。最大活跃区段数为 7。</li>\n</ul>\n</div>\n\n<p><strong class=\"example\">示例 4：</strong></p>\n\n<div class=\"example-block\">\n<p><strong>输入：</strong> <span class=\"example-io\">s = \"01010\"</span></p>\n\n<p><strong>输出：</strong> <span class=\"example-io\">4</span></p>\n\n<p><strong>解释：</strong></p>\n\n<ul>\n\t<li>字符串 <code>\"01010\"</code> → 两端加上 <code>'1'</code>&nbsp;后得到 <code>\"1010101\"</code>。</li>\n\t<li>选择 <code>\"010\"</code>，<code>\"10<u><strong>1</strong></u>0101\"</code> → <code>\"1<u><strong>000</strong></u>101\"</code> → <code>\"1<u><strong>111</strong></u>101\"</code>。</li>\n\t<li>最终的字符串去掉两端的 <code>'1'</code>&nbsp;后为 <code>\"11110\"</code>。最大活跃区段数为 4。</li>\n</ul>\n</div>\n\n<p>&nbsp;</p>\n\n<p><strong>提示：</strong></p>\n\n<ul>\n\t<li><code>1 &lt;= n == s.length &lt;= 10<sup>5</sup></code></li>\n\t<li><code>s[i]</code> 仅包含 <code>'0'</code> 或 <code>'1'</code></li>\n</ul>\n",
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target=\\\"_blank\\\">\\u300c\\u4ed3\\u9889\\u7f16\\u7a0b\\u8bed\\u8a00\\u5f00\\u53d1\\u6307\\u5357\\u300d<\\/a><\\/p>\"]}",
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