leetcode-problemset/leetcode-cn/originData/gcd-of-odd-and-even-sums.json

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            "questionId": "3995",
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            "categoryTitle": "Algorithms",
            "boundTopicId": 3761282,
            "title": "GCD of Odd and Even Sums",
            "titleSlug": "gcd-of-odd-and-even-sums",
            "content": "<p>You are given an integer <code>n</code>. Your task is to compute the <strong>GCD</strong> (greatest common divisor) of two values:</p>\n\n<ul>\n\t<li>\n\t<p><code>sumOdd</code>: the sum of the first <code>n</code> odd numbers.</p>\n\t</li>\n\t<li>\n\t<p><code>sumEven</code>: the sum of the first <code>n</code> even numbers.</p>\n\t</li>\n</ul>\n\n<p>Return the GCD of <code>sumOdd</code> and <code>sumEven</code>.</p>\n\n<p>&nbsp;</p>\n<p><strong class=\"example\">Example 1:</strong></p>\n\n<div class=\"example-block\">\n<p><strong>Input:</strong> <span class=\"example-io\">n = 4</span></p>\n\n<p><strong>Output:</strong> <span class=\"example-io\">4</span></p>\n\n<p><strong>Explanation:</strong></p>\n\n<ul>\n\t<li>Sum of the first 4 odd numbers <code>sumOdd = 1 + 3 + 5 + 7 = 16</code></li>\n\t<li>Sum of the first 4 even numbers <code>sumEven = 2 + 4 + 6 + 8 = 20</code></li>\n</ul>\n\n<p>Hence, <code>GCD(sumOdd, sumEven) = GCD(16, 20) = 4</code>.</p>\n</div>\n\n<p><strong class=\"example\">Example 2:</strong></p>\n\n<div class=\"example-block\">\n<p><strong>Input:</strong> <span class=\"example-io\">n = 5</span></p>\n\n<p><strong>Output:</strong> <span class=\"example-io\">5</span></p>\n\n<p><strong>Explanation:</strong></p>\n\n<ul>\n\t<li>Sum of the first 5 odd numbers <code>sumOdd = 1 + 3 + 5 + 7 + 9 = 25</code></li>\n\t<li>Sum of the first 5 even numbers <code>sumEven = 2 + 4 + 6 + 8 + 10 = 30</code></li>\n</ul>\n\n<p>Hence, <code>GCD(sumOdd, sumEven) = GCD(25, 30) = 5</code>.</p>\n</div>\n\n<p>&nbsp;</p>\n<p><strong>Constraints:</strong></p>\n\n<ul>\n\t<li><code>1 &lt;= n &lt;= 10​​​​​​​00</code></li>\n</ul>\n",
            "translatedTitle": "奇数和与偶数和的最大公约数",
            "translatedContent": "<p>给你一个整数 <code>n</code>。请你计算以下两个值的&nbsp;<strong>最大公约数</strong>（GCD）：</p>\n\n<ul>\n\t<li>\n\t<p><code>sumOdd</code>：前 <code>n</code> 个奇数的总和。</p>\n\t</li>\n\t<li>\n\t<p><code>sumEven</code>：前 <code>n</code> 个偶数的总和。</p>\n\t</li>\n</ul>\n\n<p>返回 <code>sumOdd</code> 和 <code>sumEven</code> 的 GCD。</p>\n\n<p>&nbsp;</p>\n\n<p><strong class=\"example\">示例 1：</strong></p>\n\n<div class=\"example-block\">\n<p><strong>输入：</strong> <span class=\"example-io\">n = 4</span></p>\n\n<p><strong>输出：</strong> <span class=\"example-io\">4</span></p>\n\n<p><strong>解释：</strong></p>\n\n<ul>\n\t<li>前 4 个奇数的总和 <code>sumOdd = 1 + 3 + 5 + 7 = 16</code></li>\n\t<li>前 4 个偶数的总和 <code>sumEven = 2 + 4 + 6 + 8 = 20</code></li>\n</ul>\n\n<p>因此，<code>GCD(sumOdd, sumEven) = GCD(16, 20) = 4</code>。</p>\n</div>\n\n<p><strong class=\"example\">示例 2：</strong></p>\n\n<div class=\"example-block\">\n<p><strong>输入：</strong> <span class=\"example-io\">n = 5</span></p>\n\n<p><strong>输出：</strong> <span class=\"example-io\">5</span></p>\n\n<p><strong>解释：</strong></p>\n\n<ul>\n\t<li>前 5 个奇数的总和 <code>sumOdd = 1 + 3 + 5 + 7 + 9 = 25</code></li>\n\t<li>前 5 个偶数的总和 <code>sumEven = 2 + 4 + 6 + 8 + 10 = 30</code></li>\n</ul>\n\n<p>因此，<code>GCD(sumOdd, sumEven) = GCD(25, 30) = 5</code>。</p>\n</div>\n\n<p>&nbsp;</p>\n\n<p><strong>提示：</strong></p>\n\n<ul>\n\t<li><code>1 &lt;= n &lt;= 1000</code></li>\n</ul>\n",
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                "The first <code>n</code> odd numbers sum to <code>n * n</code>",
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