leetcode-problemset/leetcode-cn/originData/find-minimum-log-transportation-cost.json

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            "categoryTitle": "Algorithms",
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            "title": "Find Minimum Log Transportation Cost",
            "titleSlug": "find-minimum-log-transportation-cost",
            "content": "<p>You are given integers <code>n</code>, <code>m</code>, and <code>k</code>.</p>\n\n<p>There are two logs of lengths <code>n</code> and <code>m</code> units, which need to be transported in three trucks where each truck can carry one log with length <strong>at most</strong> <code>k</code> units.</p>\n\n<p>You may cut the logs into smaller pieces, where the cost of cutting a log of length <code>x</code> into logs of length <code>len1</code> and <code>len2</code> is <code>cost = len1 * len2</code> such that <code>len1 + len2 = x</code>.</p>\n\n<p>Return the <strong>minimum total cost</strong> to distribute the logs onto the trucks. If the logs don&#39;t need to be cut, the total cost is 0.</p>\n\n<p>&nbsp;</p>\n<p><strong class=\"example\">Example 1:</strong></p>\n\n<div class=\"example-block\">\n<p><strong>Input:</strong> <span class=\"example-io\">n = 6, m = 5, k = 5</span></p>\n\n<p><strong>Output:</strong> <span class=\"example-io\">5</span></p>\n\n<p><strong>Explanation:</strong></p>\n\n<p>Cut the log with length 6 into logs with length 1 and 5, at a cost equal to <code>1 * 5 == 5</code>. Now the three logs of length 1, 5, and 5 can fit in one truck each.</p>\n</div>\n\n<p><strong class=\"example\">Example 2:</strong></p>\n\n<div class=\"example-block\">\n<p><strong>Input:</strong> <span class=\"example-io\">n = 4, m = 4, k = 6</span></p>\n\n<p><strong>Output:</strong> <span class=\"example-io\">0</span></p>\n\n<p><strong>Explanation:</strong></p>\n\n<p>The two logs can fit in the trucks already, hence we don&#39;t need to cut the logs.</p>\n</div>\n\n<p>&nbsp;</p>\n<p><strong>Constraints:</strong></p>\n\n<ul>\n\t<li><code>2 &lt;= k &lt;= 10<sup>5</sup></code></li>\n\t<li><code>1 &lt;= n, m &lt;= 2 * k</code></li>\n\t<li>The input is generated such that it is always possible to transport the logs.</li>\n</ul>\n",
            "translatedTitle": "木材运输的最小成本",
            "translatedContent": "<p>给你三个整数 <code>n</code>、<code>m</code> 和 <code>k</code>。</p>\n\n<p>有两根长度分别为 <code>n</code> 和 <code>m</code> 单位的木材，需要通过三辆卡车运输。每辆卡车最多只能装载一根长度&nbsp;<strong>不超过</strong> <code>k</code> 单位的木材。</p>\n\n<p>你可以将木材切成更小的段，其中将长度为 <code>x</code> 的木材切割成长度为 <code>len1</code> 和 <code>len2</code> 的段的成本为 <code>cost = len1 * len2</code>，并且满足 <code>len1 + len2 = x</code>。</p>\n\n<p>返回将木材分配到卡车上的&nbsp;<strong>最小总成本&nbsp;</strong>。如果木材不需要切割，总成本为 0。</p>\n\n<p>&nbsp;</p>\n\n<p><strong class=\"example\">示例 1：</strong></p>\n\n<div class=\"example-block\">\n<p><strong>输入：</strong> <span class=\"example-io\">n = 6, m = 5, k = 5</span></p>\n\n<p><strong>输出：</strong> <span class=\"example-io\">5</span></p>\n\n<p><strong>解释：</strong></p>\n\n<p>将长度为 6 的木材切割成长度为 1 和 5 的两段，成本为 <code>1 * 5 == 5</code>。现在三段长度分别为 1、5 和 5 的木材可以分别装载到每辆卡车。</p>\n</div>\n\n<p><strong class=\"example\">示例 2：</strong></p>\n\n<div class=\"example-block\">\n<p><strong>输入：</strong> <span class=\"example-io\">n = 4, m = 4, k = 6</span></p>\n\n<p><strong>输出：</strong> <span class=\"example-io\">0</span></p>\n\n<p><strong>解释：</strong></p>\n\n<p>两根木材已经可以直接装载到卡车上，因此不需要切割。</p>\n</div>\n\n<p>&nbsp;</p>\n\n<p><strong>提示：</strong></p>\n\n<ul>\n\t<li><code>2 &lt;= k &lt;= 10<sup>5</sup></code></li>\n\t<li><code>1 &lt;= n, m &lt;= 2 * k</code></li>\n\t<li>输入数据保证木材总存在能被运输的方案。</li>\n</ul>\n",
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                "If both logs have a length less than <code>k</code>, cost is zero.",
                "Can we transport the logs if both logs have length greater than <code>k</code>.",
                "Otherwise, pick the log with greater length and cut it into logs with lengths <code>len1</code> and <code>len2</code> such that <code>len1 + len2</code> equals the original length.",
                "To minimize the cost <code>len1 * len2</code>, choose <code>len1</code> and <code>len2</code> as far apart as possible (e.g. <code>1</code> and <code>length−1</code>)."
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