leetcode-problemset/leetcode-cn/originData/earliest-time-to-finish-one-task.json

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        "question": {
            "questionId": "4012",
            "questionFrontendId": "3683",
            "categoryTitle": "Algorithms",
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            "title": "Earliest Time to Finish One Task",
            "titleSlug": "earliest-time-to-finish-one-task",
            "content": "<p>You are given a 2D integer array <code>tasks</code> where <code>tasks[i] = [s<sub>i</sub>, t<sub>i</sub>]</code>.</p>\n\n<p>Each <code>[s<sub>i</sub>, t<sub>i</sub>]</code> in <code>tasks</code> represents a task with start time <code>s<sub>i</sub></code> that takes <code>t<sub>i</sub></code> units of time to finish.</p>\n\n<p>Return the earliest time at which at least one task is finished.</p>\n\n<p>&nbsp;</p>\n<p><strong class=\"example\">Example 1:</strong></p>\n\n<div class=\"example-block\">\n<p><strong>Input:</strong> <span class=\"example-io\">tasks = [[1,6],[2,3]]</span></p>\n\n<p><strong>Output:</strong> <span class=\"example-io\">5</span></p>\n\n<p><strong>Explanation:</strong></p>\n\n<p>The first task starts at time <code>t = 1</code> and finishes at time <code>1 + 6 = 7</code>. The second task finishes at time <code>2 + 3 = 5</code>. You can finish one task at time 5.</p>\n</div>\n\n<p><strong class=\"example\">Example 2:</strong></p>\n\n<div class=\"example-block\">\n<p><strong>Input:</strong> <span class=\"example-io\">tasks = [[100,100],[100,100],[100,100]]</span></p>\n\n<p><strong>Output:</strong> <span class=\"example-io\">200</span></p>\n\n<p><strong>Explanation:</strong></p>\n\n<p>All three tasks finish at time <code>100 + 100 = 200</code>.</p>\n</div>\n\n<p>&nbsp;</p>\n<p><strong>Constraints:</strong></p>\n\n<ul>\n\t<li><code>1 &lt;= tasks.length &lt;= 100</code></li>\n\t<li><code>tasks[i] = [s<sub>i</sub>, t<sub>i</sub>]</code></li>\n\t<li><code>1 &lt;= s<sub>i</sub>, t<sub>i</sub> &lt;= 100</code></li>\n</ul>\n",
            "translatedTitle": "完成一个任务的最早时间",
            "translatedContent": "<p>给你一个二维整数数组 <code>tasks</code>，其中 <code>tasks[i] = [s<sub>i</sub>, t<sub>i</sub>]</code>。</p>\n\n<p>数组中的每个 <code>[s<sub>i</sub>, t<sub>i</sub>]</code> 表示一个任务，该任务的开始时间为 <code>s<sub>i</sub></code>，完成该任务需要 <code>t<sub>i</sub></code> 个时间单位。</p>\n\n<p>返回至少完成一个任务的最早时间。</p>\n\n<p>&nbsp;</p>\n\n<p><strong class=\"example\">示例 1：</strong></p>\n\n<div class=\"example-block\">\n<p><strong>输入：</strong> <span class=\"example-io\">tasks = [[1,6],[2,3]]</span></p>\n\n<p><strong>输出：</strong> <span class=\"example-io\">5</span></p>\n\n<p><strong>解释：</strong></p>\n\n<p>第一个任务从时间 <code>t = 1</code> 开始，并在 <code>1 + 6 = 7</code> 时完成。第二个任务在时间 <code>t = 2</code> 开始，并在 <code>2 + 3 = 5</code> 时完成。因此，最早完成的任务在时间 5。</p>\n</div>\n\n<p><strong class=\"example\">示例 2：</strong></p>\n\n<div class=\"example-block\">\n<p><strong>输入：</strong> <span class=\"example-io\">tasks = [[100,100],[100,100],[100,100]]</span></p>\n\n<p><strong>输出：</strong> <span class=\"example-io\">200</span></p>\n\n<p><strong>解释：</strong></p>\n\n<p>三个任务都在时间 <code>100 + 100 = 200</code> 时完成。</p>\n</div>\n\n<p>&nbsp;</p>\n\n<p><strong>提示：</strong></p>\n\n<ul>\n\t<li><code>1 &lt;= tasks.length &lt;= 100</code></li>\n\t<li><code>tasks[i] = [s<sub>i</sub>, t<sub>i</sub>]</code></li>\n\t<li><code>1 &lt;= s<sub>i</sub>, t<sub>i</sub> &lt;= 100</code></li>\n</ul>\n",
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                    "code": "class Solution {\npublic:\n    int earliestTime(vector<vector<int>>& tasks) {\n        \n    }\n};",
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                "Compute <code>finish[i] = s[i] + t[i]</code> for each task and take the minimum."
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