leetcode-problemset/leetcode-cn/originData/compute-decimal-representation.json

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        "question": {
            "questionId": "4039",
            "questionFrontendId": "3697",
            "categoryTitle": "Algorithms",
            "boundTopicId": 3793310,
            "title": "Compute Decimal Representation",
            "titleSlug": "compute-decimal-representation",
            "content": "<p>You are given a <strong>positive</strong> integer <code>n</code>.</p>\n\n<p>A positive integer is a <strong>base-10 component</strong> if it is the product of a single digit from 1 to 9 and a non-negative power of 10. For example, 500, 30, and 7 are <strong>base-10 components</strong>, while 537, 102, and 11 are not.</p>\n\n<p>Express <code>n</code> as a sum of <strong>only</strong> base-10 components, using the <strong>fewest</strong> base-10 components possible.</p>\n\n<p>Return an array containing these <strong>base-10 components</strong> in <strong>descending</strong> order.</p>\n\n<p>&nbsp;</p>\n<p><strong class=\"example\">Example 1:</strong></p>\n\n<div class=\"example-block\">\n<p><strong>Input:</strong> <span class=\"example-io\">n = 537</span></p>\n\n<p><strong>Output:</strong> <span class=\"example-io\">[500,30,7]</span></p>\n\n<p><strong>Explanation:</strong></p>\n\n<p>We can express 537 as <code>500 + 30 + 7</code>. It is impossible to express 537 as a sum using fewer than 3 base-10 components.</p>\n</div>\n\n<p><strong class=\"example\">Example 2:</strong></p>\n\n<div class=\"example-block\">\n<p><strong>Input:</strong> <span class=\"example-io\">n = 102</span></p>\n\n<p><strong>Output:</strong> <span class=\"example-io\">[100,2]</span></p>\n\n<p><strong>Explanation:</strong></p>\n\n<p>We can express 102 as <code>100 + 2</code>. 102 is not a base-10 component, which means 2 base-10 components are needed.</p>\n</div>\n\n<p><strong class=\"example\">Example 3:</strong></p>\n\n<div class=\"example-block\">\n<p><strong>Input:</strong> <span class=\"example-io\">n = 6</span></p>\n\n<p><strong>Output:</strong> <span class=\"example-io\">[6]</span></p>\n\n<p><strong>Explanation:</strong></p>\n\n<p>6 is a base-10 component.</p>\n</div>\n\n<p>&nbsp;</p>\n<p><strong>Constraints:</strong></p>\n\n<ul>\n\t<li><code>1 &lt;= n &lt;= 10<sup>9</sup></code></li>\n</ul>\n",
            "translatedTitle": "计算十进制表示",
            "translatedContent": "<p>给你一个&nbsp;<strong>正整数&nbsp;</strong><code>n</code>。</p>\n\n<p>如果一个正整数可以表示为 1 到 9 的单个数字和 10 的非负整数次幂的乘积，则称这个整数是一个&nbsp;<strong>10 进制分量</strong>。例如，500、30 和 7 是&nbsp;<strong>10 进制分量&nbsp;</strong>，而 537、102 和 11 则不是。</p>\n\n<p>请将&nbsp;<code>n</code>&nbsp;表示为若干&nbsp;<strong>仅由&nbsp;</strong>10 进制分量组成的和，且使用的 10 进制分量个数&nbsp;<strong>最少&nbsp;</strong>。</p>\n\n<p>返回一个包含这些&nbsp;<strong>10 进制分量 </strong>的数组，并按分量大小&nbsp;<strong>降序&nbsp;</strong>排列。</p>\n\n<p>&nbsp;</p>\n\n<p><strong class=\"example\">示例 1：</strong></p>\n\n<div class=\"example-block\">\n<p><strong>输入：</strong><span class=\"example-io\">n = 537</span></p>\n\n<p><strong>输出：</strong><span class=\"example-io\">[500,30,7]</span></p>\n\n<p><strong>解释：</strong></p>\n\n<p>我们可以将 537 表示为<code>500 + 30 + 7</code>。无法用少于 3 个 10 进制分量表示 537。</p>\n</div>\n\n<p><strong class=\"example\">示例 2：</strong></p>\n\n<div class=\"example-block\">\n<p><strong>输入：</strong><span class=\"example-io\">n = 102</span></p>\n\n<p><strong>输出：</strong><span class=\"example-io\">[100,2]</span></p>\n\n<p><strong>解释：</strong></p>\n\n<p>我们可以将 102 表示为<code>100 + 2</code>。102 不是一个 10 进制分量，因此需要 2 个 10 进制分量。</p>\n</div>\n\n<p><strong class=\"example\">示例 3：</strong></p>\n\n<div class=\"example-block\">\n<p><strong>输入：</strong><span class=\"example-io\">n = 6</span></p>\n\n<p><strong>输出：</strong><span class=\"example-io\">[6]</span></p>\n\n<p><strong>解释：</strong></p>\n\n<p>6 是一个 10 进制分量。</p>\n</div>\n\n<p>&nbsp;</p>\n\n<p><strong>提示：</strong></p>\n\n<ul>\n\t<li><code>1 &lt;= n &lt;= 10<sup>9</sup></code></li>\n</ul>\n",
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                    "lang": "C++",
                    "langSlug": "cpp",
                    "code": "class Solution {\npublic:\n    vector<int> decimalRepresentation(int n) {\n        \n    }\n};",
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                    "code": "class Solution {\n    public int[] decimalRepresentation(int n) {\n        \n    }\n}",
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                    "code": "class Solution {\n\n    /**\n     * @param Integer $n\n     * @return Integer[]\n     */\n    function decimalRepresentation($n) {\n        \n    }\n}",
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            "hints": [
                "Break the number down digit by digit starting from the ones place.",
                "Each nonzero digit contributes a base-10 component.",
                "Collect all components and return them in descending order."
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