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https://gitee.com/coder-xiaomo/leetcode-problemset
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189 lines
32 KiB
JSON
189 lines
32 KiB
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"title": "Best Time to Buy and Sell Stock using Strategy",
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"content": "<p>You are given two integer arrays <code>prices</code> and <code>strategy</code>, where:</p>\n\n<ul>\n\t<li><code>prices[i]</code> is the price of a given stock on the <code>i<sup>th</sup></code> day.</li>\n\t<li><code>strategy[i]</code> represents a trading action on the <code>i<sup>th</sup></code> day, where:\n\t<ul>\n\t\t<li><code>-1</code> indicates buying one unit of the stock.</li>\n\t\t<li><code>0</code> indicates holding the stock.</li>\n\t\t<li><code>1</code> indicates selling one unit of the stock.</li>\n\t</ul>\n\t</li>\n</ul>\n\n<p>You are also given an <strong>even</strong> integer <code>k</code>, and may perform <strong>at most one</strong> modification to <code>strategy</code>. A modification consists of:</p>\n\n<ul>\n\t<li>Selecting exactly <code>k</code> <strong>consecutive</strong> elements in <code>strategy</code>.</li>\n\t<li>Set the <strong>first</strong> <code>k / 2</code> elements to <code>0</code> (hold).</li>\n\t<li>Set the <strong>last</strong> <code>k / 2</code> elements to <code>1</code> (sell).</li>\n</ul>\n\n<p>The <strong>profit</strong> is defined as the <strong>sum</strong> of <code>strategy[i] * prices[i]</code> across all days.</p>\n\n<p>Return the <strong>maximum</strong> possible profit you can achieve.</p>\n\n<p><strong>Note:</strong> There are no constraints on budget or stock ownership, so all buy and sell operations are feasible regardless of past actions.</p>\n\n<p> </p>\n<p><strong class=\"example\">Example 1:</strong></p>\n\n<div class=\"example-block\">\n<p><strong>Input:</strong> <span class=\"example-io\">prices = [4,2,8], strategy = [-1,0,1], k = 2</span></p>\n\n<p><strong>Output:</strong> <span class=\"example-io\">10</span></p>\n\n<p><strong>Explanation:</strong></p>\n\n<table style=\"border: 1px solid black;\">\n\t<thead>\n\t\t<tr>\n\t\t\t<th style=\"border: 1px solid black;\">Modification</th>\n\t\t\t<th style=\"border: 1px solid black;\">Strategy</th>\n\t\t\t<th style=\"border: 1px solid black;\">Profit Calculation</th>\n\t\t\t<th style=\"border: 1px solid black;\">Profit</th>\n\t\t</tr>\n\t</thead>\n\t<tbody>\n\t\t<tr>\n\t\t\t<td style=\"border: 1px solid black;\">Original</td>\n\t\t\t<td style=\"border: 1px solid black;\">[-1, 0, 1]</td>\n\t\t\t<td style=\"border: 1px solid black;\">(-1 × 4) + (0 × 2) + (1 × 8) = -4 + 0 + 8</td>\n\t\t\t<td style=\"border: 1px solid black;\">4</td>\n\t\t</tr>\n\t\t<tr>\n\t\t\t<td style=\"border: 1px solid black;\">Modify [0, 1]</td>\n\t\t\t<td style=\"border: 1px solid black;\">[0, 1, 1]</td>\n\t\t\t<td style=\"border: 1px solid black;\">(0 × 4) + (1 × 2) + (1 × 8) = 0 + 2 + 8</td>\n\t\t\t<td style=\"border: 1px solid black;\">10</td>\n\t\t</tr>\n\t\t<tr>\n\t\t\t<td style=\"border: 1px solid black;\">Modify [1, 2]</td>\n\t\t\t<td style=\"border: 1px solid black;\">[-1, 0, 1]</td>\n\t\t\t<td style=\"border: 1px solid black;\">(-1 × 4) + (0 × 2) + (1 × 8) = -4 + 0 + 8</td>\n\t\t\t<td style=\"border: 1px solid black;\">4</td>\n\t\t</tr>\n\t</tbody>\n</table>\n\n<p>Thus, the maximum possible profit is 10, which is achieved by modifying the subarray <code>[0, 1]</code>.</p>\n</div>\n\n<p><strong class=\"example\">Example 2:</strong></p>\n\n<div class=\"example-block\">\n<p><strong>Input:</strong> <span class=\"example-io\">prices = [5,4,3], strategy = [1,1,0], k = 2</span></p>\n\n<p><strong>Output:</strong> <span class=\"example-io\">9</span></p>\n\n<p><strong>Explanation:</strong></p>\n\n<div class=\"example-block\">\n<table style=\"border: 1px solid black;\">\n\t<thead>\n\t\t<tr>\n\t\t\t<th style=\"border: 1px solid black;\">Modification</th>\n\t\t\t<th style=\"border: 1px solid black;\">Strategy</th>\n\t\t\t<th style=\"border: 1px solid black;\">Profit Calculation</th>\n\t\t\t<th style=\"border: 1px solid black;\">Profit</th>\n\t\t</tr>\n\t</thead>\n\t<tbody>\n\t\t<tr>\n\t\t\t<td style=\"border: 1px solid black;\">Original</td>\n\t\t\t<td style=\"border: 1px solid black;\">[1, 1, 0]</td>\n\t\t\t<td style=\"border: 1px solid black;\">(1 × 5) + (1 × 4) + (0 × 3) = 5 + 4 + 0</td>\n\t\t\t<td style=\"border: 1px solid black;\">9</td>\n\t\t</tr>\n\t\t<tr>\n\t\t\t<td style=\"border: 1px solid black;\">Modify [0, 1]</td>\n\t\t\t<td style=\"border: 1px solid black;\">[0, 1, 0]</td>\n\t\t\t<td style=\"border: 1px solid black;\">(0 × 5) + (1 × 4) + (0 × 3) = 0 + 4 + 0</td>\n\t\t\t<td style=\"border: 1px solid black;\">4</td>\n\t\t</tr>\n\t\t<tr>\n\t\t\t<td style=\"border: 1px solid black;\">Modify [1, 2]</td>\n\t\t\t<td style=\"border: 1px solid black;\">[1, 0, 1]</td>\n\t\t\t<td style=\"border: 1px solid black;\">(1 × 5) + (0 × 4) + (1 × 3) = 5 + 0 + 3</td>\n\t\t\t<td style=\"border: 1px solid black;\">8</td>\n\t\t</tr>\n\t</tbody>\n</table>\n\n<p>Thus, the maximum possible profit is 9, which is achieved without any modification.</p>\n</div>\n</div>\n\n<p> </p>\n<p><strong>Constraints:</strong></p>\n\n<ul>\n\t<li><code>2 <= prices.length == strategy.length <= 10<sup>5</sup></code></li>\n\t<li><code>1 <= prices[i] <= 10<sup>5</sup></code></li>\n\t<li><code>-1 <= strategy[i] <= 1</code></li>\n\t<li><code>2 <= k <= prices.length</code></li>\n\t<li><code>k</code> is even</li>\n</ul>\n",
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"translatedTitle": "按策略买卖股票的最佳时机",
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"translatedContent": "<p>给你两个整数数组 <code>prices</code> 和 <code>strategy</code>,其中:</p>\n\n<ul>\n\t<li><code>prices[i]</code> 表示第 <code>i</code> 天某股票的价格。</li>\n\t<li><code>strategy[i]</code> 表示第 <code>i</code> 天的交易策略,其中:\n\t<ul>\n\t\t<li><code>-1</code> 表示买入一单位股票。</li>\n\t\t<li><code>0</code> 表示持有股票。</li>\n\t\t<li><code>1</code> 表示卖出一单位股票。</li>\n\t</ul>\n\t</li>\n</ul>\n\n<p>同时给你一个 <strong>偶数 </strong>整数 <code>k</code>,你可以对 <code>strategy</code> 进行 <strong>最多一次 </strong>修改。一次修改包括:</p>\n\n<ul>\n\t<li>选择 <code>strategy</code> 中恰好 <code>k</code> 个 <strong>连续 </strong>元素。</li>\n\t<li>将前 <code>k / 2</code> 个元素设为 <code>0</code>(持有)。</li>\n\t<li>将后 <code>k / 2</code> 个元素设为 <code>1</code>(卖出)。</li>\n</ul>\n\n<p><strong>利润 </strong>定义为所有天数中 <code>strategy[i] * prices[i]</code> 的 <strong>总和 </strong>。</p>\n\n<p>返回你可以获得的 <strong>最大 </strong>可能利润。</p>\n\n<p><strong>注意:</strong> 没有预算或股票持有数量的限制,因此所有买入和卖出操作均可行,无需考虑过去的操作。</p>\n\n<p> </p>\n\n<p><strong class=\"example\">示例 1:</strong></p>\n\n<div class=\"example-block\">\n<p><strong>输入:</strong> <span class=\"example-io\">prices = [4,2,8], strategy = [-1,0,1], k = 2</span></p>\n\n<p><strong>输出:</strong> <span class=\"example-io\">10</span></p>\n\n<p><strong>解释:</strong></p>\n\n<table style=\"border: 1px solid black;\">\n\t<thead>\n\t\t<tr>\n\t\t\t<th style=\"border: 1px solid black;\">修改</th>\n\t\t\t<th style=\"border: 1px solid black;\">策略</th>\n\t\t\t<th style=\"border: 1px solid black;\">利润计算</th>\n\t\t\t<th style=\"border: 1px solid black;\">利润</th>\n\t\t</tr>\n\t</thead>\n\t<tbody>\n\t\t<tr>\n\t\t\t<td style=\"border: 1px solid black;\">原始</td>\n\t\t\t<td style=\"border: 1px solid black;\">[-1, 0, 1]</td>\n\t\t\t<td style=\"border: 1px solid black;\">(-1 × 4) + (0 × 2) + (1 × 8) = -4 + 0 + 8</td>\n\t\t\t<td style=\"border: 1px solid black;\">4</td>\n\t\t</tr>\n\t\t<tr>\n\t\t\t<td style=\"border: 1px solid black;\">修改 [0, 1]</td>\n\t\t\t<td style=\"border: 1px solid black;\">[0, 1, 1]</td>\n\t\t\t<td style=\"border: 1px solid black;\">(0 × 4) + (1 × 2) + (1 × 8) = 0 + 2 + 8</td>\n\t\t\t<td style=\"border: 1px solid black;\">10</td>\n\t\t</tr>\n\t\t<tr>\n\t\t\t<td style=\"border: 1px solid black;\">修改 [1, 2]</td>\n\t\t\t<td style=\"border: 1px solid black;\">[-1, 0, 1]</td>\n\t\t\t<td style=\"border: 1px solid black;\">(-1 × 4) + (0 × 2) + (1 × 8) = -4 + 0 + 8</td>\n\t\t\t<td style=\"border: 1px solid black;\">4</td>\n\t\t</tr>\n\t</tbody>\n</table>\n\n<p>因此,最大可能利润是 10,通过修改子数组 <code>[0, 1]</code> 实现。</p>\n</div>\n\n<p><strong class=\"example\">示例 2:</strong></p>\n\n<div class=\"example-block\">\n<p><strong>输入:</strong> <span class=\"example-io\">prices = [5,4,3], strategy = [1,1,0], k = 2</span></p>\n\n<p><strong>输出:</strong> <span class=\"example-io\">9</span></p>\n\n<p><strong>解释:</strong></p>\n\n<div class=\"example-block\">\n<table style=\"border: 1px solid black;\">\n\t<thead>\n\t\t<tr>\n\t\t\t<th style=\"border: 1px solid black;\">修改</th>\n\t\t\t<th style=\"border: 1px solid black;\">策略</th>\n\t\t\t<th style=\"border: 1px solid black;\">利润计算</th>\n\t\t\t<th style=\"border: 1px solid black;\">利润</th>\n\t\t</tr>\n\t</thead>\n\t<tbody>\n\t\t<tr>\n\t\t\t<td style=\"border: 1px solid black;\">原始</td>\n\t\t\t<td style=\"border: 1px solid black;\">[1, 1, 0]</td>\n\t\t\t<td style=\"border: 1px solid black;\">(1 × 5) + (1 × 4) + (0 × 3) = 5 + 4 + 0</td>\n\t\t\t<td style=\"border: 1px solid black;\">9</td>\n\t\t</tr>\n\t\t<tr>\n\t\t\t<td style=\"border: 1px solid black;\">修改 [0, 1]</td>\n\t\t\t<td style=\"border: 1px solid black;\">[0, 1, 0]</td>\n\t\t\t<td style=\"border: 1px solid black;\">(0 × 5) + (1 × 4) + (0 × 3) = 0 + 4 + 0</td>\n\t\t\t<td style=\"border: 1px solid black;\">4</td>\n\t\t</tr>\n\t\t<tr>\n\t\t\t<td style=\"border: 1px solid black;\">修改 [1, 2]</td>\n\t\t\t<td style=\"border: 1px solid black;\">[1, 0, 1]</td>\n\t\t\t<td style=\"border: 1px solid black;\">(1 × 5) + (0 × 4) + (1 × 3) = 5 + 0 + 3</td>\n\t\t\t<td style=\"border: 1px solid black;\">8</td>\n\t\t</tr>\n\t</tbody>\n</table>\n\n<p>因此,最大可能利润是 9,无需任何修改即可达成。</p>\n</div>\n</div>\n\n<p> </p>\n\n<p><strong>提示:</strong></p>\n\n<ul>\n\t<li><code>2 <= prices.length == strategy.length <= 10<sup>5</sup></code></li>\n\t<li><code>1 <= prices[i] <= 10<sup>5</sup></code></li>\n\t<li><code>-1 <= strategy[i] <= 1</code></li>\n\t<li><code>2 <= k <= prices.length</code></li>\n\t<li><code>k</code> 是偶数</li>\n</ul>\n",
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