leetcode-problemset/leetcode-cn/originData/[no content]minimum-number-of-coins-for-fruits-ii.json

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            "questionFrontendId": "2969",
            "categoryTitle": "Algorithms",
            "boundTopicId": 2574188,
            "title": "Minimum Number of Coins for Fruits II",
            "titleSlug": "minimum-number-of-coins-for-fruits-ii",
            "content": null,
            "translatedTitle": "购买水果需要的最少金币数 II",
            "translatedContent": null,
            "isPaidOnly": true,
            "difficulty": "Hard",
            "likes": 0,
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            "topicTags": [
                {
                    "name": "Queue",
                    "slug": "queue",
                    "translatedName": "队列",
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                    "name": "Array",
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                    "translatedName": "数组",
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                    "name": "Dynamic Programming",
                    "slug": "dynamic-programming",
                    "translatedName": "动态规划",
                    "__typename": "TopicTagNode"
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                {
                    "name": "Monotonic Queue",
                    "slug": "monotonic-queue",
                    "translatedName": "单调队列",
                    "__typename": "TopicTagNode"
                },
                {
                    "name": "Heap (Priority Queue)",
                    "slug": "heap-priority-queue",
                    "translatedName": "堆（优先队列）",
                    "__typename": "TopicTagNode"
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            "hints": [
                "Use DP + Fenwick tree.",
                "There is another creative solution using multiset instead of Fenwick.",
                "Imagine we want to calculate <code>dp[i]</code> which is the answer to the problem for the first <code>i</code> fruits.",
                "If we buy <code>l<sup>th</sup></code> fruit from the set of indices: <code>[(i + 1) / 2, (i + 1) / 2 + 1, (i + 1) / 2 + 2, ..., i - 1]</code>, then we can get fruits <code>l + 1, l + 2, ..., i</code> for free.",
                "We just need to get all the first <code>l - 1</code> fruits as well and the minimum price for that, is <code>dp[l - 1]</code>.",
                "So at the index <code>i</code>, we are looking for such an index <code>l</code> that <code>dp[l - 1] + prices[l]</code> is as minimum as possible.",
                "We can store these values in a multiset and update the values in it."
            ],
            "solution": null,
            "status": null,
            "sampleTestCase": "[3,1,2]",
            "metaData": "{\n  \"name\": \"minimumCoins\",\n  \"params\": [\n    {\n      \"name\": \"prices\",\n      \"type\": \"integer[]\"\n    }\n  ],\n  \"return\": {\n    \"type\": \"integer\"\n  }\n}",
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