{ "data": { "question": { "questionId": "2777", "questionFrontendId": "2670", "boundTopicId": null, "title": "Find the Distinct Difference Array", "titleSlug": "find-the-distinct-difference-array", "content": "
You are given a 0-indexed array nums
of length n
.
The distinct difference array of nums
is an array diff
of length n
such that diff[i]
is equal to the number of distinct elements in the suffix nums[i + 1, ..., n - 1]
subtracted from the number of distinct elements in the prefix nums[0, ..., i]
.
Return the distinct difference array of nums
.
Note that nums[i, ..., j]
denotes the subarray of nums
starting at index i
and ending at index j
inclusive. Particularly, if i > j
then nums[i, ..., j]
denotes an empty subarray.
\n
Example 1:
\n\n\nInput: nums = [1,2,3,4,5]\nOutput: [-3,-1,1,3,5]\nExplanation: For index i = 0, there is 1 element in the prefix and 4 distinct elements in the suffix. Thus, diff[0] = 1 - 4 = -3.\nFor index i = 1, there are 2 distinct elements in the prefix and 3 distinct elements in the suffix. Thus, diff[1] = 2 - 3 = -1.\nFor index i = 2, there are 3 distinct elements in the prefix and 2 distinct elements in the suffix. Thus, diff[2] = 3 - 2 = 1.\nFor index i = 3, there are 4 distinct elements in the prefix and 1 distinct element in the suffix. Thus, diff[3] = 4 - 1 = 3.\nFor index i = 4, there are 5 distinct elements in the prefix and no elements in the suffix. Thus, diff[4] = 5 - 0 = 5.\n\n\n
Example 2:
\n\n\nInput: nums = [3,2,3,4,2]\nOutput: [-2,-1,0,2,3]\nExplanation: For index i = 0, there is 1 element in the prefix and 3 distinct elements in the suffix. Thus, diff[0] = 1 - 3 = -2.\nFor index i = 1, there are 2 distinct elements in the prefix and 3 distinct elements in the suffix. Thus, diff[1] = 2 - 3 = -1.\nFor index i = 2, there are 2 distinct elements in the prefix and 2 distinct elements in the suffix. Thus, diff[2] = 2 - 2 = 0.\nFor index i = 3, there are 3 distinct elements in the prefix and 1 distinct element in the suffix. Thus, diff[3] = 3 - 1 = 2.\nFor index i = 4, there are 3 distinct elements in the prefix and no elements in the suffix. Thus, diff[4] = 3 - 0 = 3.\n\n\n
\n
Constraints:
\n\n1 <= n == nums.length <= 50
1 <= nums[i] <= 50
Compiled with clang 11
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Your code is compiled with level two optimization (-O2
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Most standard library headers are already included automatically for your convenience.
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