Given an array of strings words and a string s, determine if s is an acronym of words.
The string s is considered an acronym of words if it can be formed by concatenating the first character of each string in words in order. For example, "ab" can be formed from ["apple", "banana"], but it can't be formed from ["bear", "aardvark"].
Return true if s is an acronym of words, and false otherwise.
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Example 1:
\n\n\nInput: words = ["alice","bob","charlie"], s = "abc"\nOutput: true\nExplanation: The first character in the words "alice", "bob", and "charlie" are 'a', 'b', and 'c', respectively. Hence, s = "abc" is the acronym. \n\n\n
Example 2:
\n\n\nInput: words = ["an","apple"], s = "a"\nOutput: false\nExplanation: The first character in the words "an" and "apple" are 'a' and 'a', respectively. \nThe acronym formed by concatenating these characters is "aa". \nHence, s = "a" is not the acronym.\n\n\n
Example 3:
\n\n\nInput: words = ["never","gonna","give","up","on","you"], s = "ngguoy"\nOutput: true\nExplanation: By concatenating the first character of the words in the array, we get the string "ngguoy". \nHence, s = "ngguoy" is the acronym.\n\n\n
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Constraints:
\n\n1 <= words.length <= 1001 <= words[i].length <= 101 <= s.length <= 100words[i] and s consist of lowercase English letters.words, and compare the resulting concatenation to s.Compiled with clang 11 using the latest C++ 20 standard.
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