{ "data": { "question": { "questionId": "3238", "questionFrontendId": "2977", "categoryTitle": "Algorithms", "boundTopicId": 2575710, "title": "Minimum Cost to Convert String II", "titleSlug": "minimum-cost-to-convert-string-ii", "content": "
You are given two 0-indexed strings source
and target
, both of length n
and consisting of lowercase English characters. You are also given two 0-indexed string arrays original
and changed
, and an integer array cost
, where cost[i]
represents the cost of converting the string original[i]
to the string changed[i]
.
You start with the string source
. In one operation, you can pick a substring x
from the string, and change it to y
at a cost of z
if there exists any index j
such that cost[j] == z
, original[j] == x
, and changed[j] == y
. You are allowed to do any number of operations, but any pair of operations must satisfy either of these two conditions:
source[a..b]
and source[c..d]
with either b < c
or d < a
. In other words, the indices picked in both operations are disjoint.source[a..b]
and source[c..d]
with a == c
and b == d
. In other words, the indices picked in both operations are identical.Return the minimum cost to convert the string source
to the string target
using any number of operations. If it is impossible to convert source
to target
, return -1
.
Note that there may exist indices i
, j
such that original[j] == original[i]
and changed[j] == changed[i]
.
\n
Example 1:
\n\n\nInput: source = "abcd", target = "acbe", original = ["a","b","c","c","e","d"], changed = ["b","c","b","e","b","e"], cost = [2,5,5,1,2,20]\nOutput: 28\nExplanation: To convert "abcd" to "acbe", do the following operations:\n- Change substring source[1..1] from "b" to "c" at a cost of 5.\n- Change substring source[2..2] from "c" to "e" at a cost of 1.\n- Change substring source[2..2] from "e" to "b" at a cost of 2.\n- Change substring source[3..3] from "d" to "e" at a cost of 20.\nThe total cost incurred is 5 + 1 + 2 + 20 = 28. \nIt can be shown that this is the minimum possible cost.\n\n\n
Example 2:
\n\n\nInput: source = "abcdefgh", target = "acdeeghh", original = ["bcd","fgh","thh"], changed = ["cde","thh","ghh"], cost = [1,3,5]\nOutput: 9\nExplanation: To convert "abcdefgh" to "acdeeghh", do the following operations:\n- Change substring source[1..3] from "bcd" to "cde" at a cost of 1.\n- Change substring source[5..7] from "fgh" to "thh" at a cost of 3. We can do this operation because indices [5,7] are disjoint with indices picked in the first operation.\n- Change substring source[5..7] from "thh" to "ghh" at a cost of 5. We can do this operation because indices [5,7] are disjoint with indices picked in the first operation, and identical with indices picked in the second operation.\nThe total cost incurred is 1 + 3 + 5 = 9.\nIt can be shown that this is the minimum possible cost.\n\n\n
Example 3:
\n\n\nInput: source = "abcdefgh", target = "addddddd", original = ["bcd","defgh"], changed = ["ddd","ddddd"], cost = [100,1578]\nOutput: -1\nExplanation: It is impossible to convert "abcdefgh" to "addddddd".\nIf you select substring source[1..3] as the first operation to change "abcdefgh" to "adddefgh", you cannot select substring source[3..7] as the second operation because it has a common index, 3, with the first operation.\nIf you select substring source[3..7] as the first operation to change "abcdefgh" to "abcddddd", you cannot select substring source[1..3] as the second operation because it has a common index, 3, with the first operation.\n\n\n
\n
Constraints:
\n\n1 <= source.length == target.length <= 1000
source
, target
consist only of lowercase English characters.1 <= cost.length == original.length == changed.length <= 100
1 <= original[i].length == changed[i].length <= source.length
original[i]
, changed[i]
consist only of lowercase English characters.original[i] != changed[i]
1 <= cost[i] <= 106
给你两个下标从 0 开始的字符串 source
和 target
,它们的长度均为 n
并且由 小写 英文字母组成。
另给你两个下标从 0 开始的字符串数组 original
和 changed
,以及一个整数数组 cost
,其中 cost[i]
代表将字符串 original[i]
更改为字符串 changed[i]
的成本。
你从字符串 source
开始。在一次操作中,如果 存在 任意 下标 j
满足 cost[j] == z
、original[j] == x
以及 changed[j] == y
,你就可以选择字符串中的 子串 x
并以 z
的成本将其更改为 y
。 你可以执行 任意数量 的操作,但是任两次操作必须满足 以下两个 条件 之一 :
source[a..b]
和 source[c..d]
,满足 b < c
或 d < a
。换句话说,两次操作中选择的下标 不相交 。source[a..b]
和 source[c..d]
,满足 a == c
且 b == d
。换句话说,两次操作中选择的下标 相同 。返回将字符串 source
转换为字符串 target
所需的 最小 成本。如果不可能完成转换,则返回 -1
。
注意,可能存在下标 i
、j
使得 original[j] == original[i]
且 changed[j] == changed[i]
。
\n\n
示例 1:
\n\n\n输入:source = \"abcd\", target = \"acbe\", original = [\"a\",\"b\",\"c\",\"c\",\"e\",\"d\"], changed = [\"b\",\"c\",\"b\",\"e\",\"b\",\"e\"], cost = [2,5,5,1,2,20]\n输出:28\n解释:将 \"abcd\" 转换为 \"acbe\",执行以下操作:\n- 将子串 source[1..1] 从 \"b\" 改为 \"c\" ,成本为 5 。\n- 将子串 source[2..2] 从 \"c\" 改为 \"e\" ,成本为 1 。\n- 将子串 source[2..2] 从 \"e\" 改为 \"b\" ,成本为 2 。\n- 将子串 source[3..3] 从 \"d\" 改为 \"e\" ,成本为 20 。\n产生的总成本是 5 + 1 + 2 + 20 = 28 。 \n可以证明这是可能的最小成本。\n\n\n
示例 2:
\n\n\n输入:source = \"abcdefgh\", target = \"acdeeghh\", original = [\"bcd\",\"fgh\",\"thh\"], changed = [\"cde\",\"thh\",\"ghh\"], cost = [1,3,5]\n输出:9\n解释:将 \"abcdefgh\" 转换为 \"acdeeghh\",执行以下操作:\n- 将子串 source[1..3] 从 \"bcd\" 改为 \"cde\" ,成本为 1 。\n- 将子串 source[5..7] 从 \"fgh\" 改为 \"thh\" ,成本为 3 。可以执行此操作,因为下标 [5,7] 与第一次操作选中的下标不相交。\n- 将子串 source[5..7] 从 \"thh\" 改为 \"ghh\" ,成本为 5 。可以执行此操作,因为下标 [5,7] 与第一次操作选中的下标不相交,且与第二次操作选中的下标相同。\n产生的总成本是 1 + 3 + 5 = 9 。\n可以证明这是可能的最小成本。\n\n\n
示例 3:
\n\n\n输入:source = \"abcdefgh\", target = \"addddddd\", original = [\"bcd\",\"defgh\"], changed = [\"ddd\",\"ddddd\"], cost = [100,1578]\n输出:-1\n解释:无法将 \"abcdefgh\" 转换为 \"addddddd\" 。\n如果选择子串 source[1..3] 执行第一次操作,以将 \"abcdefgh\" 改为 \"adddefgh\" ,你无法选择子串 source[3..7] 执行第二次操作,因为两次操作有一个共用下标 3 。\n如果选择子串 source[3..7] 执行第一次操作,以将 \"abcdefgh\" 改为 \"abcddddd\" ,你无法选择子串 source[1..3] 执行第二次操作,因为两次操作有一个共用下标 3 。\n\n\n
\n\n
提示:
\n\n1 <= source.length == target.length <= 1000
source
、target
均由小写英文字母组成1 <= cost.length == original.length == changed.length <= 100
1 <= original[i].length == changed[i].length <= source.length
original[i]
、changed[i]
均由小写英文字母组成original[i] != changed[i]
1 <= cost[i] <= 106
original
and changed
arrays a unique id. There are at most 2 * m
unique strings in total where m
is the length of the arrays. We can put them into a hash map to assign ids.",
"We can pre-compute the smallest costs between all pairs of unique strings using Floyd Warshall algorithm in O(m ^ 3)
time complexity.",
"Let dp[i]
be the smallest cost to change the first i
characters (prefix) of source
into target
, leaving the suffix untouched.\r\nWe have dp[0] = 0
.\r\ndp[i] = min(\r\ndp[i - 1] if (source[i - 1] == target[i - 1]),\r\ndp[j-1] + cost[x][y] where x is the id of source[j..(i - 1)] and y is the id of target e[j..(i - 1)])\r\n)
.\r\nIf neither of the two conditions is satisfied, dp[i] = infinity
.",
"We can use Trie to check for the second condition in O(1)
.",
"The answer is dp[n]
where n
is source.length
."
],
"solution": null,
"status": null,
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