{ "data": { "question": { "questionId": "3228", "questionFrontendId": "3002", "categoryTitle": "Algorithms", "boundTopicId": 2592238, "title": "Maximum Size of a Set After Removals", "titleSlug": "maximum-size-of-a-set-after-removals", "content": "

You are given two 0-indexed integer arrays nums1 and nums2 of even length n.

\n\n

You must remove n / 2 elements from nums1 and n / 2 elements from nums2. After the removals, you insert the remaining elements of nums1 and nums2 into a set s.

\n\n

Return the maximum possible size of the set s.

\n\n

 

\n

Example 1:

\n\n
\nInput: nums1 = [1,2,1,2], nums2 = [1,1,1,1]\nOutput: 2\nExplanation: We remove two occurences of 1 from nums1 and nums2. After the removals, the arrays become equal to nums1 = [2,2] and nums2 = [1,1]. Therefore, s = {1,2}.\nIt can be shown that 2 is the maximum possible size of the set s after the removals.\n
\n\n

Example 2:

\n\n
\nInput: nums1 = [1,2,3,4,5,6], nums2 = [2,3,2,3,2,3]\nOutput: 5\nExplanation: We remove 2, 3, and 6 from nums1, as well as 2 and two occurrences of 3 from nums2. After the removals, the arrays become equal to nums1 = [1,4,5] and nums2 = [2,3,2]. Therefore, s = {1,2,3,4,5}.\nIt can be shown that 5 is the maximum possible size of the set s after the removals.\n
\n\n

Example 3:

\n\n
\nInput: nums1 = [1,1,2,2,3,3], nums2 = [4,4,5,5,6,6]\nOutput: 6\nExplanation: We remove 1, 2, and 3 from nums1, as well as 4, 5, and 6 from nums2. After the removals, the arrays become equal to nums1 = [1,2,3] and nums2 = [4,5,6]. Therefore, s = {1,2,3,4,5,6}.\nIt can be shown that 6 is the maximum possible size of the set s after the removals.\n
\n\n

 

\n

Constraints:

\n\n\n", "translatedTitle": "移除后集合的最多元素数", "translatedContent": "

给你两个下标从 0 开始的整数数组 nums1nums2 ,它们的长度都是偶数 n

\n\n

你必须从 nums1 中移除 n / 2 个元素,同时从 nums2 中也移除 n / 2 个元素。移除之后,你将 nums1nums2 中剩下的元素插入到集合 s 中。

\n\n

返回集合 s可能的 最多 包含多少元素。

\n\n

 

\n\n

示例 1:

\n\n
\n输入:nums1 = [1,2,1,2], nums2 = [1,1,1,1]\n输出:2\n解释:从 nums1 和 nums2 中移除两个 1 。移除后,数组变为 nums1 = [2,2] 和 nums2 = [1,1] 。因此,s = {1,2} 。\n可以证明,在移除之后,集合 s 最多可以包含 2 个元素。\n
\n\n

示例 2:

\n\n
\n输入:nums1 = [1,2,3,4,5,6], nums2 = [2,3,2,3,2,3]\n输出:5\n解释:从 nums1 中移除 2、3 和 6 ,同时从 nums2 中移除两个 3 和一个 2 。移除后,数组变为 nums1 = [1,4,5] 和 nums2 = [2,3,2] 。因此,s = {1,2,3,4,5} 。\n可以证明,在移除之后,集合 s 最多可以包含 5 个元素。 \n
\n\n

示例 3:

\n\n
\n输入:nums1 = [1,1,2,2,3,3], nums2 = [4,4,5,5,6,6]\n输出:6\n解释:从 nums1 中移除 1、2 和 3 ,同时从 nums2 中移除 4、5 和 6 。移除后,数组变为 nums1 = [1,2,3] 和 nums2 = [4,5,6] 。因此,s = {1,2,3,4,5,6} 。\n可以证明,在移除之后,集合 s 最多可以包含 6 个元素。 
\n\n

 

\n\n

提示:

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