You are given a 0-indexed 2D integer matrix grid of size 3 * 3, representing the number of stones in each cell. The grid contains exactly 9 stones, and there can be multiple stones in a single cell.
In one move, you can move a single stone from its current cell to any other cell if the two cells share a side.
\n\nReturn the minimum number of moves required to place one stone in each cell.
\n\n\n
Example 1:
\n![\"\"](\"https://assets.leetcode.com/uploads/2023/08/23/example1-3.svg\")
\n\nInput: grid = [[1,1,0],[1,1,1],[1,2,1]]\nOutput: 3\nExplanation: One possible sequence of moves to place one stone in each cell is: \n1- Move one stone from cell (2,1) to cell (2,2).\n2- Move one stone from cell (2,2) to cell (1,2).\n3- Move one stone from cell (1,2) to cell (0,2).\nIn total, it takes 3 moves to place one stone in each cell of the grid.\nIt can be shown that 3 is the minimum number of moves required to place one stone in each cell.\n\n\n
Example 2:
\n![\"\"](\"https://assets.leetcode.com/uploads/2023/08/23/example2-2.svg\")
\n\nInput: grid = [[1,3,0],[1,0,0],[1,0,3]]\nOutput: 4\nExplanation: One possible sequence of moves to place one stone in each cell is:\n1- Move one stone from cell (0,1) to cell (0,2).\n2- Move one stone from cell (0,1) to cell (1,1).\n3- Move one stone from cell (2,2) to cell (1,2).\n4- Move one stone from cell (2,2) to cell (2,1).\nIn total, it takes 4 moves to place one stone in each cell of the grid.\nIt can be shown that 4 is the minimum number of moves required to place one stone in each cell.\n\n\n
\n
Constraints:
\n\ngrid.length == grid[i].length == 30 <= grid[i][j] <= 9grid is equal to 9.4 cells with more than one stone.",
"Let a be the number of cells containing more than one stone, and b be the number of cells containing no stones. b^a ≤ 6561. Use this fact to come up with a bruteforce.",
"For all empty cells, bruteforce over all possible cells from which a stone can come. Note that a stone will always come from a cell containing at least 2 stones."
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